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muminat
4 years ago
15

Help pls with number seven :3

Mathematics
2 answers:
juin [17]4 years ago
8 0
Since the number after the decimal is greater than 5. Therefore you have to round 7 by adding 1 so

the answer is 638.
Debora [2.8K]4 years ago
8 0
Your rounding since 7 is a bigger number it’s 638
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Please answer please
Anvisha [2.4K]

Answer:

8 = m, No solution

Step-by-step explanation:

1. -88 = -3(4m + 5) - (1 - 3m)

-88 = -12m - 15 - 1 + 3m : distributed into parentheses

-88 = -9m - 16 : combined like terms

+16           + 16 : adding to cancel out

-72 = -9m

/-9       /-9 : dividing by -9 to cancel

8 = m

2. -4(5k - 7) + 2k = -2(9k + 5)

-20k + 28 + 2k = -18k - 10 : distributed into parentheses

-18k + 28 = -18k - 10 : combined like terms

       + 10            + 10 : adding to cancel out

-18k + 38 = -18k

+18k            +18k : adding to cancel out

38 = 0k (No solution)

         

5 0
2 years ago
This is for number 7
Aneli [31]
182.5 + 50 = 232.5. 267.5 was spent
6 0
3 years ago
Read 2 more answers
PLEASE HELP mee !!!
vitfil [10]

Answer:

(-4,-5)

Step-by-step explanation:

The slope of the line passing through (3,5) and (-2,1) would be:

It would be:

y2 - y1 / 2 and x2 - x1 / 2

= 1 -5 / 2 and -2 -3 /2

= -4/2 and -5/2

= (-4,-5)

Hope this helped :3

6 0
3 years ago
Read 2 more answers
Alex and Ben were given a total of £240. They shared in the ratio 5:7
Pavel [41]
Berl s : T L 240<span> + 12- = fac

</span>
5 0
4 years ago
A traffic engineer records a sample of the types of vehicles that cross a bridge. She counts 112 passenger cars, 18 light trucks
Bond [772]

Answer:

<em>The approximate probability that a random vehicle is a passenger car is 74.67%</em>

Step-by-step explanation:

<u>Probability</u>

The traffic engineer records 112 passenger cars, 18 light trucks, and 20 heavy trucks. The total of vehicles recorded is n=112+18+20 = 150.

We are required to find the probability that a randomly selected vehicle crossing the bridge is a passenger car. There are 112 passenger cars, thus the probability is:

\displaystyle p=\frac{112}{150}

p = 0.7467

p = 74.67%

The approximate probability that a random vehicle is a passenger car is 74.67%

8 0
3 years ago
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