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Evgesh-ka [11]
3 years ago
13

Please help BY tomorrow

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer:

think yourself........

Step-by-step explanation:

vjcjxgsjgclnckjcljcljckj

liubo4ka [24]3 years ago
3 0
Hey I don’t know the answer but if it is on big ideas I would like to recommend “slader” for help :]
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Y equals twenty nine over five x
mote1985 [20]

Answer:

y=29/4x

Step-by-step explanation:

6 0
3 years ago
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What does it mean to write the trinomial as the product of two factors? I’m dumb lol
maks197457 [2]

To factor a trinomial in the form x2 + bx + c, find two integers, r and s, whose product is c and whose sum is b. Rewrite the trinomial as x2 + rx + sx + c and then use grouping and the distributive property to factor the polynomial. The resulting factors will be (x + r) and (x + s)

4 0
3 years ago
LCM of 3,5,8,4 in explanation​
Rufina [12.5K]

Answer:

120

Step-by-step explanation:

If you multiply these numbers you will eventually find that they all have a common multiple of 120. 120 is also the least common multiple so therefore, the lcm is 120

4 0
3 years ago
La difference de x et 7
Goryan [66]

Answer:

x-7

Step-by-step explanation:

The difference of x and 7 is written as x-7

if you are looking for the value of x and x-7=0, then x=7, but the question is lind of vague. Hipe this helps!

6 0
3 years ago
Solve the inequality. use interval notion to state the solution (x+3)^2>2(x^2+7)
OleMash [197]

Answer:

we conclude that:

x^2+6x+9>2x^2+14\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:1

Hence, (1, 5) is the solution in interval notation.

Please also check the attached graph.

Step-by-step explanation:

Given the inequality expression

\left(x+3\right)^2>\:2\left(x^2+7\right)

as

(x + 3)² = x² + 6x + 9

2(x² + 7) = 2x² + 14

so

\:x^2+6x+9\:>\:2x^2+14

rewriting in the standard form

-x^2+6x-5>0

Factor -x² + 6x - 5:  - (x - 1) (x - 5)

-\left(x-1\right)\left(x-5\right)>0

Multiply both sides by -1 (reverse the inequality)

\left(-\left(x-1\right)\left(x-5\right)\right)\left(-1\right)

Simplify

\left(x-1\right)\left(x-5\right)

so

1

Therefore, we conclude that:

x^2+6x+9>2x^2+14\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:1

Hence, (1, 5) is the solution in interval notation.

Please also check the attached graph.

4 0
3 years ago
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