5 1/2 * 3 1/4
1 + 5 . 2/2 * 1 + 3 . 4/4 = 11/2 * 13/4 = 11 . 13/2 . 4 = 143/8 = 7 + 17 . 8/8 = 17 7/8
= 17 . 875
Detailed explanation of solution:
5 1/2 * 3 1/4
Transform the first mix number to improper fraction:
5 1/2 = 1 + 5 . 2/2 = 11/2
Transform the second mix number to improper fraction:
3 1/4 = 1 + 3. 4/4 = 13/4
Multiplying two fractions:
11/2 * 13/4 = 11 . 13/2 . 4 = 143/8
Since the numerator is greater than the denominator, We convert the improper fraction to mix fraction:
143/8 = 7 + 17.8/8
= 17 7/8 (Decimal: 17. 875)
Hope that helps!!!!!! ( Answer: 17 7/8, (Decimal: 17.875)
Answer:
A system of two equations can be classified as follows
Step-by-step explanation:
If the slopes are the same but the y-intercepts are different, the system has no solution. If the slopes are different, the system has one solution. If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.
-4x -8x +17 = 23
-12x +17 = 23
-12x=6
x= -0.5
to check plug back in the equation
For this case we have the following function:
![s (V) = \sqrt [3] {V}](https://tex.z-dn.net/?f=s%20%28V%29%20%3D%20%5Csqrt%20%5B3%5D%20%7BV%7D)
This function describes the side length of the cube.
If Jason wants a cube with a minimum volume of 64 cubic centimeters, then we propose the following inequality:
![s \geq \sqrt [3] {64}](https://tex.z-dn.net/?f=s%20%5Cgeq%20%5Csqrt%20%5B3%5D%20%7B64%7D)
Rewriting we have:
![s \geq \sqrt [3] {4 ^ 3}\\s \geq4](https://tex.z-dn.net/?f=s%20%5Cgeq%20%5Csqrt%20%5B3%5D%20%7B4%20%5E%203%7D%5C%5Cs%20%5Cgeq4)
Answer:
Option B
