Express as a function of a different angle 0
Cos(157)
2 answers:
![\bf \textit{Cofunction Identities} \\\\ sin\left(90^o-\theta\right)=cos(\theta) \qquad cos\left(90^o-\theta\right)=sin(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ cos(157)\implies cos(90^o+67^o)\implies cos[90^o-(-67^o)] \\\\\\ sin(-67^o)\implies -sin(67^o)](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BCofunction%20Identities%7D%20%5C%5C%5C%5C%20sin%5Cleft%2890%5Eo-%5Ctheta%5Cright%29%3Dcos%28%5Ctheta%29%20%5Cqquad%20cos%5Cleft%2890%5Eo-%5Ctheta%5Cright%29%3Dsin%28%5Ctheta%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20cos%28157%29%5Cimplies%20cos%2890%5Eo%2B67%5Eo%29%5Cimplies%20cos%5B90%5Eo-%28-67%5Eo%29%5D%20%5C%5C%5C%5C%5C%5C%20sin%28-67%5Eo%29%5Cimplies%20-sin%2867%5Eo%29)
you can check the example in the picture below, why the cosine of the complementary angle is equals to the sine of its sibling.
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glad i could help!
