Geometry help please?
1 answer:
You might be interested in
The phrases that are inequalities are:
B) -2 < 2
D) 7w > 5.6
E) f - 4 - 7 > 7 - 4 - f
<h3></h3><h3>Which of the following phrases are inequalities?</h3>
First, we define an equation as:
Where P and Q are two expressions.
On the other hand, an inequality can be:
These are inequalities because now the expressions P and Q can (and in some cases must) be different.
With that in mind, the phrases that are inequalities are:
B) -2 < 2
D) 7w > 5.6
E) f - 4 - 7 > 7 - 4 - f
As you can see, in these 3 we have the "lower than" or "larger than" symbols used, so these represent inequalities.
If you want to learn more about inequalities:
#SPJ1
The total surface area of a coin can be solve by using this formula
Surface Area = Area Front + Area Back + Area Side
Surface Area = 2Area Front/Back + Area Side
The Area of the Front and Back of the coin can be solve by using the formula of a circle which is
And the Area of a Side of the coin can be solve by using the formula
A = πd x thickness
We will solve first the surface area of a $5 coin.
note: 2.5 cm = 25 mm
Surface Area = 2(π(d/2)^2) + πd x thickness
= 2(π(12.5)^2) + 25π x 3
= 2 (156.25π) + 75π
=312.50π + 75π
= 387.50π
Surface Area of $5 coin is 387.50π sq mm
We will next solve for surface area of a 50 cents.
note: 2 cm = 20 mm
Surface Area = 2(π(d/2)^2) + πd x thickness
= 2(π(10)^2) + 20π x 1.5
= 2 (100π) + 30π
= 200π + 30π
= 230π
The surface area of a 50 cents is 230π sq mm.
Therefore, the ratio of the total surface area of $5 coin to 50 cents is
387.50π sq mm : 230π sq mm
Surface Area = Area Front + Area Back + Area Side
Surface Area = 2Area Front/Back + Area Side
The Area of the Front and Back of the coin can be solve by using the formula of a circle which is
And the Area of a Side of the coin can be solve by using the formula
A = πd x thickness
We will solve first the surface area of a $5 coin.
note: 2.5 cm = 25 mm
Surface Area = 2(π(d/2)^2) + πd x thickness
= 2(π(12.5)^2) + 25π x 3
= 2 (156.25π) + 75π
=312.50π + 75π
= 387.50π
Surface Area of $5 coin is 387.50π sq mm
We will next solve for surface area of a 50 cents.
note: 2 cm = 20 mm
Surface Area = 2(π(d/2)^2) + πd x thickness
= 2(π(10)^2) + 20π x 1.5
= 2 (100π) + 30π
= 200π + 30π
= 230π
The surface area of a 50 cents is 230π sq mm.
Therefore, the ratio of the total surface area of $5 coin to 50 cents is
387.50π sq mm : 230π sq mm