The radius of the sphere decreases at the rate of 6 m/ sec
That is, 
Surface Area of the sphere of radius r is given by 
Differentiating with respect to t,


8x51. 8x50=? 8x5=40. 40 x 10 = 400 8x50=400. 8x1=8 400+8=408.
5(2x-8)+15=-15 -15 in both sides
5(2x-8)=-30 /5
2x-8=-6 +8
2x=2 /2
x=1
I hope it helps
I was just in the same situation, you got this. the answer is A.
Answer:
h=p/(mg)
Step-by-step explanation:
P=mgh
solving for h,
h=p/(mg)