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2 years ago

Create a equation using this graph?

Mathematics

1 answer:

Setler79 [48]2 years ago

7 0

The formula for a straight line is y=mx+b, where m is the slope and b is the y-intercept.

To find out the slope, we use a formula known as rise/run.

Rise means how high a point goes between any two points and run is how far the space is between any two points.

We can see that there are two points give to us. Now we ask our self how high do we have to go to reach the second points’ height. If we count it we go five UP. Meaning that the rise is positive 5.
Now we see how far the two points are. If we count it, we go 1 space the LEFT meaning -1 since going left on a graph means x is getting smaller.

Now that we have he two values, we put them into rise/run

5/-1=-5

So our value of m is -5
Meaning y=-5x+b

We still have our value of b to find and we can do this by choosing any one point on the graph and substituting it into the equation. We know that one of our points is (3,0)

We put these into the equation

y=-5x+b
0=-15+b
b=15

Therefore, y=-5x+15

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

devlian [24]

Answer:

The rocket will reach its maximum height after 6.13 seconds

Step-by-step explanation:

To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height

∵ y is the height of the rocket after launch, x seconds

∵ y = -16x² + 196x + 126

- Differentiate y with respect to x

∴ y' = -16(2)x + 196

∴ y' = -32x + 196

- Equate y' by 0

∴ 0 = -32x + 196

- Add 32x to both sides

∴ 32x = 196

- Divide both sides by 32

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

∴ The rocket will reach its maximum height after 6.13 seconds

There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = $-\frac{b}{2a}$ and k is the value of y at x = h and k is the maximum/minimum value

∵ a = -16 , b = 196

∴ $h=-\frac{196}{2(-16)}$

∴ h = 6.125

∵ h is the value of x at the maximum height

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

4 0

3 years ago

PLZZ HELP ME

dimulka [17.4K]

Answer:

125/100 X 105 = 131.25

loan total = $131.25

3 0

2 years ago

Write the Slope-Intercept and Point-Slope forms of the line passing through the point (-3, 2) and having a slope of -4/5

weeeeeb [17]

Answer:

slope-intercept: $y=\frac{-4}{5} x-\frac{2}{5}$

point-slope: $y-2=\frac{-4}{5} (x+3)$

Step-by-step explanation:

The slope-intercept form of a line is written as y = mx + b, where m is the slope and b is the y-intercept.

The point-slope form of a line is written as y - y1 = m(x - x1), where (x1, y1) is a given point and m is the slope.

Here, we see that the slope is -4/5, which means that m = -4/5. Since we're given a point (-3, 2), let's go ahead and just write the point-slope form already. (x1, y1) = (-3, 2) so x1 = -3 and y1 = 2. Then:

y - y1 = m(x - x1)

y - 2 = (-4/5) * (x + 3)

$y-2=\frac{-4}{5} (x+3)$

Now, we want to find the slope-intercept form, so we need to figure out the y-intercept. Well, first, let's plug in what we know:

y = mx + b

y = (-4/5)x + b

Any point on this line will satisfy the above equation. Since (-3, 2) is on this line, if we plug -3 in for x and 2 in for y, the equation should hold true, so we can solve for b:

y = (-4/5)x + b

2 = (-4/5) * (-3) + b

2 = 12/5 + b

b = -2/5

So, the y-intercept is -2/5. Then the slope-intercept form is:

$y=\frac{-4}{5} x-\frac{2}{5}$

Thus, our two equations are:

slope-intercept: $y=\frac{-4}{5} x-\frac{2}{5}$

point-slope: $y-2=\frac{-4}{5} (x+3)$

8 0

2 years ago

Help needed now with Math question.

saveliy_v [14]

Answer:

is the last one

Step-by-step explanation:

5 0

2 years ago

Factor the expression shown below completely.

Andrew [12]

I need question for the "factor" problem

7 0

2 years ago

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