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Julli [10]
2 years ago
15

A rectangle has a width of nine units in the length of 40 units what is the length of a diagonal

Mathematics
2 answers:
shepuryov [24]2 years ago
5 0

Answer:

Applying the Pythagorean theorem, the diagonal is calculated by:

D = sqrt(40^2 + 9^2) = 41

Hope this helps!

:)

8_murik_8 [283]2 years ago
4 0

Answer:

41

Step-by-step explanation:

Imagine a right triangle with legs length  9 and 40, and hypotenuse is the diagonal length c.

a^2+b^2=c^2

9^2+40^2=c^2

81+1600=c^2

1681=c^2

sqrt both sides

41=c

The length of the diagonal is 41 units

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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
Convert 55° 16' 30" into radian measure.​
Colt1911 [192]

Answer:

55° 16' 30" = 0.9648 radians .

Step-by-step explanation:

8 0
3 years ago
2 of a dozen eggs are cracked. What percent of the carton is NOT cracked using the percent proportion
levacccp [35]

If 2 of 12 eggs are cracked, then 10 are not cracked.

SO

10/12=5/6=about 0.83

0.83 of total eggs not cracked is also equivalent to 83 percent as asked in the problem :)

6 0
2 years ago
Kelvin can carry a basket 5 feet rachel can carry it 3 feet further than kelvin daniel can carry it half as far s rachel is it r
Ksenya-84 [330]
I think it eould be 17 feet. 5 plus 8 plus 4 is 17.
6 0
3 years ago
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