Q5 - 6: I'm guessing that it's asking us how many less than right angles, right angles, or more than right angles are present in the shapes given in question 5 and 6.
Keep in mind that right angles are exactly 90 degrees. Less than a right triangle is less than 90 degrees ( x < 90) and more than a right triangle is more than 90 degrees (x > 90) View the attachment for further demonstration and explanation.
Based on this, I think you (or your sister) need to re-check question 5. There are no right angles present there, and the lack of the box and L shaped angles indicate this. You are on the right track for number 6 though as only 2 right triangles are present.
For number 8, Kaylee (lol, feels weird saying that since my name is Kaylee), is incorrect. There are no right angles. You can further explain and elaborate on this using the information I supplied you with.
A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
2x + 5y = -3 ⇒ 2x + 5y = -3
1x + 8y = 4 ⇒ <u>2x + 16y = 8
</u> -<u>11y</u> = <u>-11 </u>
-11 -11
y = 1
2x + 5(1) = -3
2x + 5 = -3
<u> -5 -5</u>
<u>2x</u> = <u>-8</u>
2 2
x = -4
(x, y) = (-4, 1)
2x + 1y = 7 ⇒ 2x + 1y = 7
1x - 2y = -14 ⇒ <u>2x - 4y = -28</u>
<u>5y</u> = <u>35</u>
5 5
y = 7
2x + 7 = 7
<u> -7 -7</u>
<u>2x</u> = <u>0</u>
2 2
x = 0
(x, y) = (0, 7)
The answer would be n<4 because 4 is greater than n.
Answer:
The number of ways are 16! or 20,922,789,888,000.
Step-by-step explanation:
Consider the provided information.
We need to determine the number of different ways 16 numbered pool balls be placed in a line on the pool table.
For the first place we have 16 balls.
For the second place we have 15 balls left.
Similarly for the third place we have 14 balls as two balls are already arranged and so on.
Or we can say that this is the permutation of 16 things taking 16 at a time.
Thus the number of ways are:
or

Hence, the number of ways are 16! or 20,922,789,888,000.