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2 years ago

The domain of the following relation: R {(6, -2), (1, 2), (-3, -4), (-3, 2)} is

1 answer:

monitta2 years ago

5 0

The domain is the set of possible inputs, i.e. the x-coordinates of the points.

Here those are 6, 1 and - 3 which in order is -3, 1, 6.

Then the answer is {-3, 1, 6}.

By the way note that this relation is not a function. Do you know why?

Because the image of -3 is not stated unambiguosly.

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20% of what number is 26?

IrinaK [193]

20% · x = 26

0,2 · x = 26 | : 0,2

x = 26 : 0,2

x = 260 : 2

x = 130

6 0

2 years ago

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If the balance of supplies at the start of the month was $900 and at the end of the month there was $450 on hand, the adjustment

Westkost [7]

A.450 If the balance of supplies at the start of the month was $900 then at the end of the month it was $450 so the answer would be 450.

Got this answer on weegy you should check it out sometimes

4 0

3 years ago

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A map show a town with an area of 3.5 inches.If the map has a scale of 1 inch:4 miles,what is the actual area of the town?

cestrela7 [59]

Answer:

The actual area of the town is 14 miles.

Step-by-step explanation:

Since you know that the scale is 1 inch:4 miles and that the map shows a town with an area of 3.5 inches, you can expressed this as follows:

Scale: 1 inch:4 miles

map area: 3.5 inches

If the actual area is x, you can say that:

3.5:x=1:4

This would be:

$\frac{3.5}{x}=\frac{1}{4}$

Now, you can solve for x:

x=(3.5*4)/1

x=14

According to this, the answer is that the actual area of the town is 14 miles.

7 0

3 years ago

Find x.______________a0

velikii [3]

Answer:

$x=4$

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

$\frac{2}{y}=\frac{y}{6}$

$y^2=12$

$y=\sqrt{12}$

$y=2\sqrt{3}$

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

$a^2+b^2=c^2$

$2^2+(2\sqrt{3})^2=c^2$

$4+12=c^2$

$c^2=16$

$c=4$

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

$x=4$

4 0

2 years ago

The volumes of two similar figures are given. The surface area of the larger figure is given. Find the surface area of the small

frez [133]

Answer:

surface area of the smaller figure ≈ 1474.64 m²

Step-by-step explanation:

The figures are similar base on the question . The surface area and the volume of the larger figure is given while only the figure of the smaller figure is given.

To find the surface area of the smaller figure we simply use the ratios. That is the scale factors.

Therefore, they are similar figure the scale factor can be represented as a:b.

The scale factor for volume is cubed.

volume of larger figure/volume of the small figure = a³/b³

4536/2625 = a³/b³

a/b = 16.5535451/13.7946209

Note that for two similar solid with scale factor a:b the surface area ratio is a²: b² (the scale factor is square)

16.55²/13.79² = 2124/x

273.9025/190.1641 = 2124/x

cross multiply

273.9025x = 403908.54840

x = 403908.54840/273.9025

x = 1474.6435261

x ≈ 1474.64 m²

4 0

3 years ago