“A cylindrical bale of hay needs to be wrapped in plastic. It has a height of 9 ft. and a radius that is one-third of its height
. How many square feet of plastic is needed?”
1 answer:
Answer:
A = 226.08
Step-by-step explanation:
Assuming that you are wrapping the sides of the cylinder and the circular top and bottom, then the formula for the surface area of the cylinder is:
A=2πrh+2πr^2 so substitute for each variable A=2(3.14)(3)(9) + 2(3.14)(3)^2
notice how I substituted 3 for the radius since it is 1/3 of 9 (the height)
Solving we get A = 169.56 + 56.52 = 226.08
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