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Temka [501]
3 years ago
13

Help on this question please?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

im not fully sure but I'd say it is 9(5+0.78)

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Y_Kistochka [10]

Answer:

12 cows and 5 chickens

8 0
3 years ago
Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?
Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: y = 3 \cos(10 (x -\pi))

We can assume the parent function to be:

y = \cos (x)

The new function can be represented as:

y = A*\cos((\frac{2\pi}{B})(x-c))

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

y = A*\cos((\frac{2\pi}{B})(x-c)) to y = 3 \cos(10 (x -\pi))

A = 3

c = \pi

\frac{2\pi}{B} = 10

Solve for B

B = \frac{2\pi}{10}

B = \frac{\pi}{5}

Using the calculated values of A,\ B\ and\ c. This implies that, the following transformations occur on the parent function:

  • <em>Vertically stretched by </em>3<em />
  • <em>Horizontally compressed by </em>\frac{\pi}{5}<em />
  • <em>Right shifted by </em>\pi<em />
5 0
3 years ago
Read 2 more answers
Heellppppppp pLLSsssssssssss
Nonamiya [84]
It is b I'm pretty sure
3 0
4 years ago
Read 2 more answers
Help now now now!!!!!!!!!!!!!!
WARRIOR [948]
The answer is 2. Here's why:

First if all, anything to the power of 0 is 1.
So n^0=1.
You need to plug in 3 for m, so then 6(3)^-1.
3^-1=1/3.
6 × 1/3= 6/3=2
2×1=2.
3 0
4 years ago
Read 2 more answers
Dr. Denscombe randomly assigned 10 participants to drink a caffeinated beverage and another 10 participants to drink a noncaffei
weqwewe [10]

Answer: t = 10

Step-by-step explanation:m

 Given that; n₁ = 10, n₂ = 10

ж₁ = 50, ж₂ = 30

Sˣ₁ = 20, Sˣ₂ = 20

Now using TEST STATISTICS

t = (ж₁ - ж₂) / √ ( Sˣ₁/n₁ + Sˣ₂/n₂ )

so we substitute our figures

t = ( 50 - 30 ) / √ ( 20/10 + 20/10 )

t = 20 / √4

t = 10

6 0
3 years ago
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