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Temka [501]
2 years ago
13

Help on this question please?

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
6 0

Answer:

im not fully sure but I'd say it is 9(5+0.78)

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Find the volume of the triangular prism​
Otrada [13]

Answer:

1,848

Step-by-step explanation:

volume = ( \frac{1}{2}  \times a \times b) \times h \\  = ( \frac{1}{2}  \times 7 \times 24) \times 22 \\  divide \: 2 \: and \: 24 \: by \: 2 \\  = (1 \times 7 \times 12) \times 22 \\  = (84) \times 22 \\  = 1,848 \\ volume \:  = 1,848

6 0
2 years ago
Let X be a positive continuous random variable with density fXpxq. Let Y " lnpXq. (a) Find the density fY pyq of Y in terms of t
salantis [7]

Answer:

X density = fXpxq and

Y" =InpXq

Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"

fX = In

And PXq =pxq

Thus replacing x with y,

PXq = pyq

(a) Hence the density of Y is FYpyq

(b) at p0, fYpyq =fYp0q= 0

At 5s, FYpyq =5

7 0
3 years ago
Read 2 more answers
Find the area of quadrilateral ABCD
andreev551 [17]

Answer:

<em>A ≈ 28.5</em>

Step-by-step explanation:

a, b, c

P = a + b + c

Semiperimeter s = \frac{a+b+c}{2}

A = \sqrt{s(s-a)(s-b)(s-c)}

~~~~~~~~~~~~~~~

P_{ABC} = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

A_{ABC} = \sqrt{7(7-4.3)(7-2.89)(7-6.81)} = √14.75901 ≈ 3.84

P_{BCD} = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

A_{BCD} = \sqrt{11.49(11.49-8.59)(11.49-7.58)(11.49-6.81)} = √609.7343148 ≈ 24.6928

A_{ABCD} = 3.84 + 24.6928 ≈ <em>28.5</em>

3 0
2 years ago
A car is traveling at a constant velocity. After two hours the car has traveled 90 miles. After five hours the car has traveled
Crazy boy [7]
After 2 hrs, the car has traveled 90 miles....that means the car travels 90/2 = 45 miles per hr. After 7 hrs...the car has traveled 7 * 45 = 315 miles
8 0
3 years ago
Fifteen of the 60 dogs at the shelter are purebred. What<br> percent of the dogs are purebred?
Aleks [24]
60/15=4 meaning 25% of the dogs are purebreed
4 0
3 years ago
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