Answer:

Step-by-step explanation:
Given
![\sqrt[3]{217}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B217%7D)
Required
Solve
Linear approximated as:

Take:

So:
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Substitute 216 for x
![f(x) = \sqrt[3]{216}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7B216%7D)

So, we have:



To calculate f'(x);
We have:
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Rewrite as:

Differentiate

Split


Substitute 216 for x



So:





The mean would be 5
Reason for this is that the mean is when all data is summed up then divided by how many data points there are
So 4+4+7=15
Then divide by 3 would equal 5
I hope this helps!
Answer:
-9/5
Step-by-step explanation:
Step 1: Take the LCM in the denominator
6/5-3
multiply the numerator and denominator by 5 to make the denominator 5.
<u>6</u>-<u>3</u> (x5)
5 1 (x5)
=<u>6-15</u>
5
= <u>-9</u>
5
!!
60$. These are my equations :
600 * 0.2 = 120 ; 600 - 120 = 480
Then...
600 * 0.1 = 60 ; 600 - 60 = 540
Which then became....
540 - 480 = 60