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Alika [10]
3 years ago
7

John and Matt are going to fill a pool with 2 different sized hoses. John can fill the pool in 5 hours, while Matt can complete

it in 10 hours. Explain each step in solving this equation.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
The complete question is
John and Matt are going to fill a pool with 2 different sized hoses. John can fill the pool in 5 hours, while Matt can complete it in 10 hours.How long will it take both to fill the pool? Explain each step in solving this equation.

we know that
<span>John can fill the pool in --------------> 5 hours
</span>therefore
<span>I calculate the amount of pool that John fills in one hour
</span>if John can fill 100% of the  pool in----------------> 5 hours
X--------------------------------------> 1 hour
X=1/5=0.20 pool/hour

Matt  can fill the pool in --------------> 10 hours
therefore
I calculate the amount of pool that Matt  fills in one hour
if Matt can fill 100% of the  pool in----------------> 10 hours
X--------------------------------------> 1 hour
X=1/10=0.10 pool/hour

<span>adding both amounts

(0.20+0.10)=0.30 -----------> 30% pool/hour
then
</span>if both can fills 30% of the  pool in----------------> 1 hour
100%-------------------------------> X
X=100/30=3.33 hours----------> 3 hours + 19 minutes+ 48 sec

the answer is 3.33 hours (3 hours + 19 minutes+ 48 sec)

<span>The equation to determine the amount of pool filling (y) according to time (t) in hours is given by

</span><span>y=0.30*t 

</span>
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Answer:

Santos should run approximately 36.145 meters along the shore

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The rate he can swim = 0.9 m/s

Let 'x' represent the distance he runs along the shore

We have;

The time he spends running on the shore, t₁ = x/4

The time he spends swimming, t₂ = (√(60² + (50 - x)²)/0.9

The total time, T = t₁ + t₂ = x/4 + (√(60² + (50 - x)²)/0.9

To find the maximum, we have;

dT/dx = 0 = d(x/4 + (√(60² + (50 - x)²)/0.9)/dx = 1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

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