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jok3333 [9.3K]
3 years ago
6

if the. área of a triangle. is 75 square. feet and its height is 10 feet what. is base ​

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
4 0

Answer:

the base is 15 feet

Step-by-step explanation:

area=1/2base×height

75=1/2×10×h

75=5h

h=75÷5

h=15

Furkat [3]3 years ago
4 0

Answer:

15

Step-by-step explanation:

75 divided by 10 is 7.5, a triangle is always half of the base x width so we need to do 7.5 x 2, which is 15

You might be interested in
Use the bar graph. Astronauts installed 15 new tiles on the outside of the space station they spent 390 minutes on the task. eac
11111nata11111 [884]

Answer:

11. It will take about 26 minutes to install a singular tile.

12. It will take about 10 more minutes to install a light than it does to install a cable.

Step-by-step explanation:

11. Since installing 15 new tiles took a total of 390 minutes and each tile took the same amount of time, you can divide the total amount of time by the number of tiles.

390/15= 26 minutes

It will take about 26 minutes to install a single tile.

12. By looking at the chart it can be assumed that installing a light takes about 22 minutes since it is in the middle of 20 and 24 minutes. Installing a cable only takes 12 minutes.

22-12= 10 minutes

It takes about 10 minutes longer to install a light than it does a cable.

5 0
3 years ago
300 ml over 15 min is what rate of ml per hour
Mama L [17]

Answer:

1200 ml per hour

Step-by-step explanation:

To compute what rate is 300 ml over 15 mins as a rate of ml per hour, we do a rule of 3, using a variable x as that amount of ml we don't know yet. We should have everything in the same units, so instead of writing 1 hour we write 60 minutes:

\frac{300~ml}{15~min}=\frac{x~ml}{60~mins}

Now we solve for x:

\frac{300~ml}{15~min}\cdot 60~mins=x~ml

\frac{18000~ml}{15} =x~ml

1200~ml =x~ml

And so, now that we know the value of x, the rate we wanted to find is

\frac{1200~ml}{60~mins}

Which is just 1200 ml per hour.

3 0
3 years ago
I dont need help anymore
vlada-n [284]
Okay I am happy you figured out the answer!
4 0
3 years ago
Read 2 more answers
Solve the system of equations.
emmainna [20.7K]

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Explanation:</h2>

We have the following system of three linear equations:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\5~ x&+~~8~ y&+~~~~ z&~=~4\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Let's use elimination method in order to get the solution of this system of equation, so let's solve this step by step.

Step 1: Multiply first equation by -5/2 and add the result to the second equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Step 2: Multiply first equation by −2 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&-~~~3~ y&-~~~62~ z&~=~-6\end{array}

Step 3: Multiply second equation by −32 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&&+~~\frac{ 113 }{ 2 }~ z&~=~\frac{ 21 }{ 2 }\end{array}

Step 4: solve for z.

\begin{aligned}       \frac{ 113 }{ 2 } ~ z & = \frac{ 21 }{ 2 } \\      z & = \frac{ 21 }{ 113 }       \end{aligned}

Step 5: solve for y.

\begin{aligned}-2y-79z &= -11\\-2y-79\cdot \frac{ 21 }{ 113 } &= -11\\y &= -\frac{ 208 }{ 113 } \end{aligned}

Step 6: solve for x by substituting y=-\frac{208}{113} and z = \frac{21}{113} into the first equation:

2x+4(-\frac{208}{113})+32(\frac{21}{113})=6 \\ \\ 2x-\frac{832}{113}+\frac{672}{113}=6 \\ \\ 2x=6+\frac{832}{113}-\frac{672}{113} \\ \\ 2x=\frac{838}{113} \\ \\ x=\frac{319}{113}

Finally:

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Learn more:</h2>

Solving System of Equations: brainly.com/question/13121177

#LearnWithBrainly

7 0
4 years ago
What are the zeros of the polynomial function? f(x)=x^4−4x^3−22x^2+4x+21
USPshnik [31]

Answer:

{-3, -1, 1, 7}

Step-by-step explanation:

f(x)=x^4−4x^3−22x^2+4x+21  is of the fourth order, and thus we can expect four zeros.  There are various ways in which we could identify the zeros.  One would be to check each of the given possible answers and determine whether the equation takes on the value 0 in each case; any such value 0 indicates that the possible zero chosen is indeed a zero.

Important:  The Rational Root Theorem applies here.  We can assume that there are at least some rational roots, which take the form of fractions, whose numerators are plus and minus factors of the constant term, 21, and whose denominators are plus and minus factors of the coefficient of the leading term of the function (which here is just 1).  Thus, factors of the given function will be factors, plus or minus, of the constant term, 21, with the coefficient 1 of the highest power term not making any difference.  That list of factors is already given:  plus or minus 3, plus or minus 1, 0 and 7.

I will arbitrarily choose -1 and determine using synthetic division whether or not this -1 is a zero of the polynomial.  Recall that if synthetic div. produces a zero remainder, then the divisor chosen is indeed a zero of the polynomial.

      --------------------------------

-1   /   1   -4   -22    4     21

             -1      +5   18     -22

    -----------------------------------

       1      -5     -17    22    -1

Because the remainder is -1, not  0, -1 is not a zero of the given function.

We must move on and try others from the given list.  Eliminate -1 and 0.  Try 3:

      --------------------------------

3   /   1   -4   -22    4     21

             +3     -3   -75   -213

   -----------------------------------

         1      -1     -25  -71  -192

So we conclude that 3 is not a zero.


Try +1:

       --------------------------------

1   /   1   -4   -22    4     21

             +1     -3   -25  -21

   -----------------------------------

         1     -3     -25  -21   0

Since the remainder is zero, we know that +1 is a zero of the given function.

Using the same method, we can show that -3, -1, 1 and 7 are zeros.

7 0
4 years ago
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