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Murrr4er [49]
3 years ago
14

300 ml over 15 min is what rate of ml per hour

Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

1200 ml per hour

Step-by-step explanation:

To compute what rate is 300 ml over 15 mins as a rate of ml per hour, we do a rule of 3, using a variable x as that amount of ml we don't know yet. We should have everything in the same units, so instead of writing 1 hour we write 60 minutes:

\frac{300~ml}{15~min}=\frac{x~ml}{60~mins}

Now we solve for x:

\frac{300~ml}{15~min}\cdot 60~mins=x~ml

\frac{18000~ml}{15} =x~ml

1200~ml =x~ml

And so, now that we know the value of x, the rate we wanted to find is

\frac{1200~ml}{60~mins}

Which is just 1200 ml per hour.

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Answer:

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Step-by-step explanation:

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I must add though that sometimes the wind was like a roaring freight train. What is the simile in the sentence above tell about
PIT_PIT [208]

Answer: The answer is B

Step-by-step explanation:

Because it says its roaring like a freight train meaning it is loud and powerful like a train.

6 0
2 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

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This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

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Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

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When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

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\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

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Hence, one (1) of them is non-analytical at x = 2.

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3 years ago
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Answer:

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Daily production: 16 3-speed and 20 10-speed bikes

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Factory B

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