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statuscvo [17]
3 years ago
8

In △ABC , m∠A=53°,m∠B=17°, and a=27. Find the perimeter of the triangle.

Mathematics
1 answer:
sdas [7]3 years ago
6 0
Using the Law of Sines  (sinA/a=sinB/b=sinC/c) and the fact that all triangles have a sum of 180° for their angles.

The third angle is C is 180-53-17=110°

27/sin53=b/sin17=c/sin110

b=27sin17/sin53, c=27sin110/sin53

And the perimeter is a+b+c so

p=27+27sin17/sin53+27sin110/sin53 units

p≈68.65 units  (to nearest hundredth of a unit)
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Music Mart offers a better deal, given that the price of the guitar is $ 219 compared to $ 279.20 for Guitar Central.

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For a certain​ candy, 20​% of the pieces are​ yellow, 15​% are​ red, 20​% are​ blue, 20​% are​ green, and the rest are brown. ​a
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Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

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  • Yellow or Blue: \frac{20}{100} +\frac{20}{100} = \frac{40}{100}  ....add the numerators
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  • Stiped:  \frac{25}{100} .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

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\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}

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\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}

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