Question

Using the given function, select the correct set of ordered pairs for the following domain values.

Answer 1

Answer:

The set of ordered pair are { (-12,-18),(-3,-3), (0,2),(3,7),(12,22)}

Step-by-step explanation:

we have

$f(x)=\frac{5}{3}x+2$

Find the values of f(x) for the domain values

For x=-12

substitute

$f(-12)=\frac{5}{3}(-12)+2=-18$

The ordered pair is (-12,-18)

For x=-3

substitute

$f(-3)=\frac{5}{3}(-3)+2=-3$

The ordered pair is (-3,-3)

For x=0

substitute

$f(0)=\frac{5}{3}(0)+2=2$

The ordered pair is (0,2)

For x=3

substitute

$f(3)=\frac{5}{3}(3)+2=7$

The ordered pair is (3,7)

For x=12

substitute

$f(12)=\frac{5}{3}(12)+2=22$

The ordered pair is (12,22)

Answer 2

Answer with explanation:

The given function is

   $f(x)=\frac{5x}{3}+2\\\\x=-12,-3,0,3,12\\\\f(-12)=\frac{5\times -12}{3}+2\\\\f(-12)=-20+2\\\\f(-12)=-18\\\\f(-3)=\frac{5 \times -3}{3}+2\\\\f(-3)=-5+2\\\\f(-3)=-3\\\\f(0)=\frac{5\times 0}{3}+2\\\\f(0)=2\\\\f(3)=\frac{5\times 3}{3}+2\\\\f(3)=5+2\\\\f(3)=7\\\\f(12)=\frac{5\times 12}{3}+2\\\\f(12)=20+2\\\\f(12)=22$

So, the ordered pair will be

   (-12, -18),(-3,-3),(0,2),(3,7),(12,22)