Answer:
Step-by-step explanation:
um
This is an equation in STANDARD form for a circle:
(x-h)^2 + (y-k)^2 = r^2
The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa.
The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1.
(x)^2 + (y-6)^2 = 1
Answer:
{-2, - 1, 0, 1}
Step-by-step explanation:
The integer solutions will be {-2, - 1, 0, 1}
Answer:
The answer is D, E, F or it is also D to F
Step-by-step explanation:
Answer:
B. BD = 9
Step-by-step explanation:
Simply set the 2 equations equal to each other (both are congruent due to perpendicular bisector):
6x + 3 = 3x = 6
3x + 3 = 6
3x = 3
x = 1
Then substitute 1 for <em>x</em> in BD
6(1) + 3
6 + 3
BD = 9
