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nikitadnepr [17]
3 years ago
11

Which of the following correctly relates the measures of the measures of the measures of the diameter (d) and radius (r) of a ci

rcle
A) d=r/2
B) r=2d
C) r=d/2
D) d=2/r
Mathematics
2 answers:
yaroslaw [1]3 years ago
4 0

Hey!

Diameter is ½ of the radius. To find the radius when you have the diameter, divide by 2.

For example, if the diameter is 12, the the radius would be:

12 \div 2 = 6

<em>That means your answer will be C.</em>

\framebox{Answer is C) r = d/2}

lozanna [386]3 years ago
3 0

Hello! The correct answer is: \boxed{ \bf C) r=d/2} _____________________________

The radius of a circle is half the diameter. In other words, if you divide the diameter by 2, you get the radius. Thus, the correct answer is option C).

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What is the slope of a line that is parallel to the line y = x + 2?
Sauron [17]

Answer:

m = - 1

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Mathematics-Session 1: No Calculator
IRINA_888 [86]

Answer:

Think it is D I am not sure

Step-by-step explanation:

8 0
2 years ago
Bob Nale is the owner of Nale's Texaco GasTown. Bob would like to estimate the mean number of litres (L) of gasoline sold to his
Fudgin [204]

Answer:

a

  The point estimate of the population mean is  \= x  =  56

b

  The 80% confidence level is  50.57 <  \mu  < 61.43

c

  There is  80% confidence that the true population mean lies within the confidence interval.

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  18

   The  standard deviation is  \sigma  =  18 \ L

   The  sample mean is  \= x  =  56

Generally the point estimate of the population mean is equivalent to the sample mean whose value is  \= x  =  56

Given that the confidence interval is 80% then the level of significance is mathematically represented as

      \alpha  =  100 -  80

      \alpha =  20 \%

      \alpha = 0.20

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table

 The  value is   Z_{\frac{ \alpha }{2} } =  1.28

 Generally the margin of error is mathematically evaluated as

          E =  Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }

=>       E =  1.28 * \frac{18 }{\sqrt{18} }

=>       E =  5.43

     Generally the 80% confidence interval is mathematically represented as

    \= x  - E  <  \mu  < \= x  + E

=>    56  - 5.43  <  \mu  < 56  + 5.43

=>   50.57 <  \mu  < 61.43

The  interpretation is that there is  80% confidence that the true population mean lies within the limit

3 0
3 years ago
2(3 - 8y) =<br><br> What is the anwser:
spin [16.1K]

Answer:

2(3 -8y)

6 - 16y

i can't go any further

6 0
2 years ago
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