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2 years ago

X2+2x-15=0 Find the quadratic formula

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

3 0

Answer:

Step-by-step explanation:

For a quadtratic in the form of

$ax^{2} + bx + c = 0$

The solutions to this can be found using the quadratic formula:

$x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$

For the given equation, $a = 1$ , $b = 2$ , $c = -15$ . Plugging these numbers into the formula will give you the answer.

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Given: Right triangles CES and RST. In two or more complete sentences, explain what additional information is needed to prove tr

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3 years ago

Read 2 more answers

A student solved 6x+4=2(x−8) in four steps as shown:

mr_godi [17]

The first thing you should do is solve the equation yourself.

1) Distribute the 2.
6x + 4 = 2x – 16

2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16

3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
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4) Finally, divide both sides by 4
4x/4 = -12/4
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To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.

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3 years ago

Three cities form a triangle. Tom measures the distances between the three cities on a map. The distances between the three citi

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2 years ago

A team averaging 110 points is likely to do very well during the regular season. The coach of your team has hypothesized that yo

aev [14]

Answer:

1. M=108

2. μ=110

3. In the explanation.

4. Test statistic t = -1.05

5. P-value = 0.1597

Step-by-step explanation:

The question is incomplete: to solve this problem, we need the sample information: size, mean and standard deviation.

We will assume a sample size of 10 matches, a sample mean of 108 points and a sample standard deviation of 6 points.

1. The mean points is the sample points and has a value of 108 points.

2. The null hypothesis is H0: μ=110, meaning that the mean score is not significantly less from 110 points.

3. This is a hypothesis test for the population mean.

The claim is that the mean score is significantly less than 110.

Then, the null and alternative hypothesis are:

$H_0: \mu=110\\\\H_a:\mu< 110$

The significance level is 0.05.

The sample has a size n=10.

The sample mean is M=108.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6}{\sqrt{10}}=1.9$

4. Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{108-110}{1.9}=\dfrac{-2}{1.9}=-1.05$

The degrees of freedom for this sample size are:

$df=n-1=10-1=9$

5. This test is a left-tailed test, with 9 degrees of freedom and t=-1.05, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.1597) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score is significantly less than 110.

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3 years ago