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3 years ago

How do I solve this?

Mathematics

2 answers:

sp2606 [1]3 years ago

6 0

What are you trying to solve for? Area, perimeter, volume?<span />

Murrr4er [49]3 years ago

3 0

What are you trying to solve ?(area,perimeter)

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Answer:

Step-by-step explanation:

c^2 is 9, 2d is 4

9-4+3=8

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3 years ago

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3 years ago

Read 2 more answers

1. |4n-15|=|n|<br> 2. |2c+8|=|10c| <br> can you please show the work for both

Alja [10]

Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

$|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\$

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

$|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}$

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3 years ago