![[n][n+8]=0](https://tex.z-dn.net/?f=%5Bn%5D%5Bn%2B8%5D%3D0)
if either or both of
![[n]](https://tex.z-dn.net/?f=%5Bn%5D)
and
![[n+8]](https://tex.z-dn.net/?f=%5Bn%2B8%5D)
are 0, i.e. if one or both of
and
are even. But both will be even if
is even, and odd otherwise, so any even
will be a solution, e.g.
.
Eh, here's my best try for a table:
<u>Like tv</u> <u> don't like tv</u> <u>total</u>
<u>Like reading:</u> 70 10 80
<u>Don't like read</u>. <u>20</u> <u>30</u> <u>50 </u>
<u>total </u> 90 40 130
The percentage of students that like tv as well as reading is- 70 divided by 130 which gives you .538 which in percentage is 53.8%.
The probability of a student that does not prefer to watch tv as also does not like to spend their time reading is 30 over 40 which can be simplified or reduced to 3 over 4. [30/40 reduced to 3/4]
Hope this somehow helped you :)
Answer:
32
Step-by-step explanation:
16*2=32
8*4=32
Answer:
26. <u>c. 6 cm</u>
27. <u>c. 70 cm³</u>
Step-by-step explanation:
<u>Question 26</u>
- Volume = Length × Width × Height
- 360 = 10 × 6 × Width
- Width = 6 cm
- <u>c. 6 cm</u>
<u></u>
<u>Question 27</u>
- Volume = Length × Width × Height
- Volume = 7 × 5 × 2
- Volume = 70 cm³
- <u>c. 70 cm³</u>
<u></u>
<u>Question 28 (not entirely visible)</u>
