Answer:
If you need additional resources to support virtual learning, please ... 9) I can solve problems involving a system of linear inequalities. ... of the submarine is 50 ft below sea level when it starts to descend ... ft/s. It dives at that rate for 5 s. ... After the initial 5-second descent, the submarine increases its rate of ...
Step-by-step explanation:
Answer: A. 11 . 38 + 4 . 03
B. 10 + 5 . 41
D. 9 . 2 + 6 . 21
Step-by-step explanation:
Step 1
Compute the sum of the given options
a) 11 . 38 + 4 . 03 = 15.41
b) 10 + 5 . 41= 15.41
c) 12 . 38 + 2 . 93= 15.31
d) 9 . 2 + 6 . 21 =15.41
e) 7 . 54 + 6 . 87=14.41
Step 2
Eliminate the expressions that do not give a sum of 15.41 , we have
a) 11 . 38 + 4 . 03 = 15.41
b) 10 + 5 . 41= 15.41
d) 9 . 2 + 6 . 21 =15.41
Therefore, the expressions with sum of 15.41 are A, B and D
Answer:
The y intercept in P(x) =4
1.C
3.B
Answer:
7200 m
Step-by-step explanation:
as volume is l×b×h
300cm = 3m
so 6m×4m×3m= 72m
Answer:
The radial probability distribution for an electron in an atom may be zero at more than one point.
Step-by-step explanation:
If we count the number of dots in each spherical shell, we obtain the total probability of finding the electron at a given value of r. Because the surface area of each shell increases more rapidly with increasing r than the electron probability density decreases, a plot of electron probability versus r (the radial probability) shows a peak. This peak corresponds to the most probable radius for the electron.
In the attached plots, it is shown electron probability as a function of distance from the nucleus (r) in all directions (radial probability), the most probable radius increases as n increases, but the 2s and 3s orbitals have regions of significant electron probability at small values of r.