Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
1/8^2, 1/2^4 and 1/3^5
Step-by-step explanation:
Answer:
-10
Step-by-step explanation:
-4 + -3 = -7
-7 + -2 = -9
-9 + -1 = -10
Answer:
x = -3
Step-by-step explanation:
To solve this, you need to isolate the variable x, this means only one side of the equation should have the variable x. To do this, you need to do the opposite operation from what's given (if it's addition, use subraction; if it's multiplication, use division; these work vise versa)
- Subtract 9 from both sides of the equation. This gives you 10x = 4x - 18.
- Subtract 4x from both sides of the equation. This gives you 6x = -18.
- Divide both sides by 6. This gives you x = -3
The final answer is x = -3
Answer:
Yep!
Step-by-step explanation:
