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Nana76 [90]
3 years ago
12

ASAP- WILL MARK BRIANIST

Mathematics
2 answers:
kupik [55]3 years ago
7 0

Now Mark me Brainiest

Snezhnost [94]3 years ago
6 0

Answer:

20-12

35-21

40-24

Step-by-step explanation:

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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
1st<br> what does this situation refers to?
levacccp [35]
Can u go closer I can’t see
5 0
3 years ago
Solve for x.<br> I was sure the answer was 2?<br> Please show me the breakdown. THX
Murljashka [212]

Answer:

x = 8 and y = 10

Step-by-step explanation:

Since the figures are congruent:

Angle PQR = EFG

6y + x = 68

Segment QR = FG

2x - 4 = 12

Solving that:

2x - 4 = 12

2x = 16

x = 8

Replacing x in 6y + x =68

6y + 8 = 68

6y = 60

y = 10

7 0
3 years ago
Please help (20 points)
Evgesh-ka [11]

35.\\V=\dfrac{\pi r^2h}{3}\ \ \ \ |\cdot3\\\\3V=\pi r^2h\ \ \ \ |:\pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}

36.\\V=150\ m^3\\r=5\ m\\h=?\\\\\text{substitute}\\\\h=\dfrac{3\cdot150}{\pi\cdot5^2}=\dfrac{450}{25\pi}=\dfrac{18}{\pi}\approx\dfrac{18}{3}=6\ m\\\\Answer:\ The\ height\ is\ greater\ than\ a\ radius.

8 0
3 years ago
Help please..........
dem82 [27]

Answer:

Step-by-step explanation:

x is greater then -2

3 0
3 years ago
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