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3 years ago

A bag contains 8 red marbles, 4 white marbles, and 6 blue marbles. find P(red or blue)

Mathematics

1 answer:

Charra [1.4K]3 years ago

3 0

Answer:

7/9 or ~77.7778% or 0.777778

Step-by-step explanation:

First you need to find the total amount or marbles.

8+4+6=18

Next, find the sum of just the blue and red marbles.

8+6=14

Now, find the probability by dividing or simplifying the number of blue and red by the total.

14/18= 7/9 OR ~0.777778

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A right triangle includes one angle that mesures 30 degrees. What is the measure of the third angle?

Airida [17]

The third angle is 60 degrees. A triangle has 180 degrees so 180-30-90=60

5 0

3 years ago

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Suppose a shipment of 190 electronic components contains 3 defective components. To determine whether the shipment should be ac

PolarNik [594]

Answer:

0.0467

Step-by-step explanation:

Probabilty of being defective is $\frac{3}{190}$

So probability of being good is $\frac{187}{190}$

Now,

Probability that all 3 of them are good is:

$\frac{187}{190}^{3}=0.9533$

Now, to find probability of rejection, we subtract the now found probability from 1. Thus, we have:

1 - 0.9533 = 0.0467

5 0

3 years ago

Should be easy points!

Andru [333]

Answer:

Let x represent the number from the sentence.

Step-by-step explanation:

2(x) + 2(1/x) = 20/3

2x + 2/x = 20/3

multiply both sides of the equation by 3x

6x + 6 = 20x

6x - 20x + 6 = 0

6x - 18x - 2x + 6 = 0

6x(x-3 -2(x-3) = 0

(6x-2 = 0 or x-3 = 0

6x = 2 or x = 3

x = 2/6

x = 1/3

Since x represented the number

Therefore x = 1/3 or 3

4 0

2 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$