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never [62]
3 years ago
11

I need help asap D:

Mathematics
1 answer:
Airida [17]3 years ago
4 0

Answer:

F

Step-by-step explanation:

decimals are percentages and then fraction can be reduced into percentages so I did the math on all of them and f is the highest score

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The perimater of the triangle is 30cm. its sides are in the ratios 1:3:2, then find its sides​
DiKsa [7]

Answer:

1 * 5 = 5cm

3 * 5 = 15cm

2 * 5 = 10cm

Step-by-step explanation:

1+3+2 = 6

then do 30 / 6  = 5 to find one part of the ratio

1 * 5 = 5

3 * 5 = 15

2 * 5 = 10

8 0
3 years ago
Read 2 more answers
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
Y = 2/3 x -3 y = -3/2 x +2 what statement about the lines are true
Hoochie [10]

Answer:

The product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the lines

y = 2/3 x -3       --- Line 1

y = -3/2x +2      --- Line 2

<u>The slope of line 1</u>

y = 2/3 x -3       --- Line 1

By comparing with the slope-intercept form of the line equation

The slope of line 1 is: m₁ = 2/3

<u>The slope of line 2</u>

y = -3/2x +2      --- Line 2

By comparing with the slope-intercept y = mx+b form of the line equation

The slope of line 2 is: m₂ = -3/2

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = (2/3)(-3/2 )

m₁ × m₂ = -1

Thus, the product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

7 0
3 years ago
What is the slope of the ramp shown in the diagram below?
bixtya [17]

Answer:

Step-by-step explanation:

slope = \frac{vertical}{horizontal} = - \frac{3}{10} → A

The slope is negative as the ramp slopes down from left to right

3 0
3 years ago
Read 2 more answers
What is the slope-intercept equation of the line below? y - i ntercept = (0, - 4) slope = 3
Artist 52 [7]

Answer:

y = 3x -4

Step-by-step explanation:

The slope-intercept equation looks like this: y = mx +b. Where m is the slope of the function and b is the y-coordinate of the vertical intercept (where the function crosses the y-axis). Let's apply the formula:

y = mx +b

y = 3x +(-4)

y = 3x -4

4 0
3 years ago
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