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never [62]
3 years ago
11

I need help asap D:

Mathematics
1 answer:
Airida [17]3 years ago
4 0

Answer:

F

Step-by-step explanation:

decimals are percentages and then fraction can be reduced into percentages so I did the math on all of them and f is the highest score

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What is the midpoint of the line segment with the endpoints J(-9,-4) and K(7,8)?
12345 [234]

Answer:

Step-by-step explanation:

22

7 0
3 years ago
Need help ASAP!!! Will mark brainliest
Papessa [141]

A=148°

B=148°

Step-by-step explanation:

180-38=148°

because A and B are equal, they're both 148°

7 0
3 years ago
The probability distribution function for the discrete random variable where x is equal to the number of red lights drivers typi
Ivahew [28]

Using probability concepts, it is found that:

a) The missing value is 0.04.

b) The mean is of 0.37.

The distribution is given by:

P(X = 0) = 0.76

P(X = 1) = 0.15

P(X = 2) = 0.05

P(X = 3) = x

Item a:

The sum of <u>all the probabilities has to be 1</u>, that is:

\sum_{i = 0}^{3} P(X = i) = 1

Thus:

0.76 + 0.15 + 0.05 + x = 1

0.96 + x = 1

x = 0.04

The missing value is 0.04.

Item b:

The mean is given by the <u>sum of each outcome multiplied by it's probability</u>, thus:

E(X) = 0(0.76) + 1(0.15) + 2(0.05) + 3(0.04) = 0.37

The mean is of 0.37.

A similar problem is given at brainly.com/question/20709747

7 0
3 years ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
3 years ago
The container that holds the water for the football team is 1/3 full. After pouring out 6 gallons of water it is 1/9 full. How m
andriy [413]
18 gallons I am
pretty sure
5 0
3 years ago
Read 2 more answers
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