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Dafna1 [17]
3 years ago
5

6) Determine if the two figures are similar. Present an informal argument to present

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

yes they are similar

step 1: flip it across the y-axis

step 2: translate it 4 units to the right and 5 units down

step 3: dilate it by a factor of 1/2

Step-by-step explanation:

You might be interested in
Bobbie spends $9.50 on a pack of bulk candy that contains 100 pieces. How much does each piece of candy cost? Round the
Xelga [282]
$0.01

cost 9.50 —> 0.095
candy 100 —> 1

0.095 rounds to $0.01

3 0
4 years ago
Write a rule for a geometric sequence that has a 1 as its first term and a common ratio of -4. what is the seventh term of this
ivann1987 [24]

I hope first term is 1.

Hope this is your question, if not I think you will, still be able to

find an answer of your question based on this solution.

The formula for general term of a geometric sequence is,

a_{n} =a_{1} *r^{n-1}

Where, first term: a_{1} =1 and common ratio: r = -4.

So, first step is to plug in the values of a1 and r in the above formula to get the rule of this geometric sequence. Hence,

a_{n} =1 *4^{n-1}

a_{n} =4^{n-1}

So, the rule of the geometric sequence is a_{n} =4^{n-1}.

To find the seventh term, plug in n = 7 in the above rule. Therefore,

a_{7} =4^{7-1}

= 4^6

= 4096

Hope this helps you!.

6 0
3 years ago
Please help me! I would really appreciate it
ozzi

Answer:

D

Step-by-step explanation:

Using the rule of exponents

(a^nb^n)^{m} = a^{(mn)}b^{(mn)}, hence

(a^{\frac{1}{2} }b^{\frac{1}{3} })^(\frac{1}{2})

= a^{\frac{1}{2}(\frac{1}{2} ) } × b^{\frac{1}{3}(\frac{1}{2})  }

= a^{\frac{1}{4} } b^{\frac{1}{6} } → D

4 0
4 years ago
Ugh help plz I don’t get this
STatiana [176]
The answer is athe answer is a, although your mouse was in the way so slightly difficult to read
7 0
3 years ago
CAN SOMEONE PLEASE EXPLAIN THIS FOR ME PLEASE HELP
Nata [24]

The equation that describes the given polynomial is:

P(x) = x²*(x - 2)²*(x + 2)

<h3>How to find the equation for the polynomial?</h3>

Remember that a polynomial with a leading coefficient A and roots:

x₁, x₂, x₃,...,xₙ

The equation that describes the polynomial is:

P(x) = a*(x - x₁)*(x - x₂)*...*(x - xₙ)

In this case, we know that the leading coefficient is 1, and the roots are:

2, 2, 0, 0, -2.

(the first two appear two times because have a multiplicity of two).

Then we can write the equation of the polynomial as:

P(x) = 1*(x - 2)*(x - 2)*(x - 0)*(x - 0)*(x + 2)

P(x) = x²*(x - 2)²*(x + 2)

Learn more about polynomials:

brainly.com/question/4142886

#SPJ1

7 0
1 year ago
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