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Alecsey [184]
3 years ago
11

A manager samples the receipts of every fifth person who goes through the line. Out of 50 people, 4 had a mispriced item. If 1,6

00 people go to this store each day, how many people would you expect to have a mispriced item?
Mathematics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

128

Step-by-step explanation:

There are 32 50's in 1600.

So 32x4=128

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What is the vertex of function f(x)=(x-3)(x+5)?
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Answer:

( − 1 , − 16 )

Step-by-step explanation:

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A yardstick casts a shadow of 24 in. at the same time a telephone pole casts a shadow of 20 ft 8 in. What is the height of the t
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Find the x-intercept and y-intercept of the line. 3x-6y=12
Makovka662 [10]

Answer:

the y- intercept is "3" and the x- intercept is "6"

Step-by-step explanation:

5 0
3 years ago
Help quick ❗️❗️ Which sequence of transformations will change did your PQRS to figure P’Q’R’S’?
babymother [125]

Answer:

Counterclockwise rotation about the origin by 90° followed by reflection over the Y-axis ⇒ answer (D)

Step-by-step explanation:

* Lets revise the reflection and the rotation of a point

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) rotated about the origin by angle 90° counter clockwise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clockwise

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise or  

anti-clockwise around the origin

- In our problem

# The vertices of the original figure are:

  P(1 , -3) , Q (3 , -2) , R (3 ,-3) , S (2 , -4)

# The vertices of the image are:

  P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

∵ x and y are switched

∴ The figure is rotated about origin by 90°

∵ The signs of the x-coordinates and the y-coordinates

   didn't change

∴ The rotation is followed by reflection, to know about which

   axis we must to find the images after the rotation

∵ P (1 , -3) ⇒ after rotation 90° counter clockwise is (3 , 1)

∵ Q (3 , -2) ⇒ after rotation 90° counter clockwise is (2 , 3)

∵ R (3 , -3) ⇒ after rotation 90° counter clockwise is (3 , 3)

∵ S (2 , -4) ⇒ after rotation 90° counter clockwise is (4 , 2)

* The images are P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

- The sign of x-coordinates of all of them changed

∴ The rotation followed by reflection over the y-axis

* The answer is ⇒ Counterclockwise rotation about the origin

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7 0
3 years ago
Solve for a.<br> a^2=-3a+88
Sergio [31]

Answer:

a=8,-11

Step-by-step explanation:

a^2=-3a+88

a^2+3a=88

a^2+3a-88=0

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{-3\pm\sqrt{3^2-4(1)(-88)} }{2(1)}

x=\frac{-3\pm\sqrt{9+352} }{2}

x=\frac{-3\pm\sqrt{361} }{2}

x=\frac{-3\pm19 }{2}

x=-11 and x=8

Therefore, the values of a are 8 and -11.

5 0
2 years ago
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