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Rashid [163]
3 years ago
12

The circumference of a circle is 14 pi ft. Find its diameter, in feet

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
6 0

Answer:

The formula for area of a circle is:

A

=

π

r

2

, where

A

=

area,

π

=

22

7

, and

r

=

radius.

Since we know that the radius is half the diameter of a circle, we know that the radius of the given circle is

14

2

=

7

f

t

.

Hence:

A

=

π

r

2

A

=

22

7

×

7

2

A

=

22

7

×

7

×

7

A

=

22

7

×

7

×

7

A

=

22

×

7

A

=

154

Valentin [98]3 years ago
3 0

Answer:

14

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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balu736 [363]

Answer:

-x^2+15y-15

Answer if it is a ^2

Step-by-step explanation:

2x^2 + 6y - 3 -(3x^2 - 9y + 12)=

2x^2+6y-3-3x^2+9y-12=

-x^2+15y-15

is it a ^2 or a question mark

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Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
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Every 12 square inches Joseph can fit a one inch fish. The fish that he has are 3 inches long, therefore he can only fit one fish every 36 square inches. 
That means that if we take the total volume of the tank and divide it by the space that a 3 inch fish will take up, we are left with 192/36 = 5.3 fish.
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3 0
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Doreen has the option of borrowing $960 for 1 week at an APR of 350% or
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Step-by-step explanation:

Well aint no explination i just guessed man

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3 years ago
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It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

7 0
3 years ago
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