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Paul [167]
3 years ago
8

Hey I need math help I will up vote all

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0
What math help do you need?
<u>Award brainliest if helped!</u>
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A factory produces pop-its at a constant rate. After 4 hours, 3,120 pop-its have been produced. What is the unit rate? (must sho
Viktor [21]

A

Step-by-step explanation:

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2 years ago
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PLEASE HELP I'LL MARK AS THE BRAINIEST​
rodikova [14]

Answer:

c

Step-by-step explanation:

4 0
2 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
miss Akunina [59]

Answer:

a. 0.343

b. 0.657

c. 0.189

d. 0.216

e. 0.353

Step-by-step explanation:

We use the combination formula of probability distribution to solve the question.

Where P(x=r) = nCr * p^r * q^n-r

Where n = number of trials = 3 vehicles

r = desired outcome of trial which varies.

p = probability of success = 70% =0.7

q = probability of failure = 1-p = 0.3

a. Probability that all 3 vehicles passed = P(X=3)

= 3C3 * 0.7^3 * 0.3^0 = 1 * 0.343 * 1

= 0.343.

b. Probability that at least one fails = 1 - (probability that none failed)

And probability that none failed = probability that all 3 vehicles passed.

Hence Probability that at least one fails = 1 - (probability that all 3 vehicles passe)

= 1 - 0.343

= 0.657

c.) probability that exactly one pass= P(X=1)

= 3C1 * 0.7¹ * 0.3² = 3 * 0.7 * 0.09

= 0.189

d.) probability that at most One of the vehicles passed = probability that none passed + probability of one passed.

Probability that none of the vehicles passed = P(X=0)

= 3C0 * 0.7^0 * 0.3^3 = 1*1*0.027

=0.027

Probability that one passed as calculated earlier = 0.189

Hence probability that at most one vehicle passed = 0.189 + 0.027 = 0.216

e.) Probability that all three Vehicles pass given that at least one pass = (probability of all three vehicles passes) / (probability that at least one passes)

Probability that at least one pass = 1 - probability that none passed.

= 1 - 0.027

= 0.973

Hence,

Probability that all three Vehicles passed given that at least one passed = 0.343/0.973

= 0.3525 = 0.353 (3.d.p)

7 0
3 years ago
6) Simplify the following:<br> axaxbxb
Irina-Kira [14]

The simplified expression of axaxbxb is a^2b^2

<h3>How to simplify the expression?</h3>

The expression is given as;

axaxbxb

Rewrite properly as:

a * a * b * b

Evaluate the product

a^2b^2

Hence, the simplified expression of axaxbxb is a^2b^2

Read more about expressions at:

brainly.com/question/723406

#SPJ1

6 0
1 year ago
the currency in egypt is the pound. the exchange rate is approximately 6 pounds for $1. at this rate, how many dollars would you
Assoli18 [71]
Since it is 6 pounds per dollar, all you would do is divide 18 by 6 and get 3. Thus if you went to go exchange 18 pounds you would get $3 worth of US dollars.
4 0
3 years ago
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