Answer:
610cm square
Step-by-step explanation:
find the area of the square
find the area of a triangle and multiply it by 2
then add their areas
Answer:
6
Step-by-step explanation:
add all of them divided by how many numbers there are
Answer:
Domain → (-∞, ∞)
Range → (-∞, ∞)
Step-by-step explanation:
Domain of a function is defined by the x-values or input values of the graph.
Similarly, Range of the function is defined by the y-values or output values from the graph.
From the picture attached,
x - values for the line shown in the graph vary from negative infinity to positive infinity.
Therefore, Domain of the function will be → (-∞, ∞)
And for every x-value there is a y-value, so Range of the function will be same as domain (varying from negative infinity to positive infinity) → (-∞, ∞)
It would be 7:45 am. Am because she's eating breakfast and 7:45 plus 15 is 8
Answer:
Part A
x is 46°
Part B
Alternate angles are angles that are in relatively opposite locations relative to a transversal
Please see attached diagram showing alternate angles
Step-by-step explanation:
Part A
∠DRP = 110° (Given)
∠QPA = 64° (Given)
∠QPR =
Given that AB is parallel to CD, we have;
∠DRP is congruent to ∠APR (Alternate angles to a transversal RP of parallel lines AB and CD)
Therefore, ∠APR = 115°
∠APR = ∠QPA + ∠QPR (Angle addition postulate)
∴ 115° = 64° + ∠QPR
∠QPR = 110° - 64° = 46°
x = 46°
Part B.
Given that AB is parallel to CD, the lines common (that intersects) both lines are the transversal lines
The angles formed between the parallel lines and the transversal lines have special relationships based on their position with respect to each other
In the question, the angle 110° given between CD and the transversal RP, is found to at an alternate position to the angle ∠APR between the same transversal RP and AB and given that alternate angles are always equal, angle ∠APR is therefore also equal to 110°.