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2 years ago

Please help! Hard math.

Mathematics

1 answer:

Reil [10]2 years ago

5 0

Answer:

the value of digit 3 in 156.32 =

3 x 0.1 = 0.3

The value of digit 3 in 13 =

3 x 1 = 3

3/0.3=10 times

The value of digit 3 in 13 is 10 ten times the value of digit 3 in 156.32

As long as the (digit in ones/single digit) of a number is equal to 3

The value of digit 3 of it is always 10 ten times the value of digit 3 in 156.32

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Use substitution to show that 9+6(10-7x) is equivalent to 69-42x.<br><br> .

Leno4ka [110]

Answer:

hope this helps

Step-by-step explanation:

9+6(10-7x)

9+60-42x

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2 years ago

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Step-by-step explanation:

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1 year ago

If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

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1 year ago

Rewrite the expression 14m-(5+8m) without parentheses

JulijaS [17]

Answer:

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Step-by-step explanation:

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Fudgin [204]

This is a very challenging equation but I'll try my best!

<span>y-k=a(x-h)^2
$Vertex(1,1) ----\ \textgreater \ y-1=a(x-1)^2 
contains~ the ~point (0,-3) 

----\ \textgreater \ 1-1=a(0-,-3)^2 

----\ \textgreater \ 1=-2a 

----\ \textgreater \ a=1/-2

Equation: Y-1=1/-2(x-2)^2$
</span>

4 0

2 years ago