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igor_vitrenko [27]
3 years ago
8

Find the product of 3(x+4)(x-5)

Mathematics
2 answers:
valentinak56 [21]3 years ago
8 0
First distribute the 3
(3x + 12)(x - 5)
Multiply
3x{^2} - 3x - 60
ASHA 777 [7]3 years ago
4 0

For this case we have the following steps:

Step 1:

We apply distributive property, which states:

a (b + c) = ab + ac

Applying the property to the product of "3" and the first parenthesis we have:

(3x + 12) (x-5)

Step 2:

Apply distributive property again

3x ^ 2-15x + 12x-60

Step 3:

We add similar terms

3x ^ 2-3x-60

Thus, the product is given by: 3x ^ 2-3x-60

Answer:

3x ^ 2-3x-60


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The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}, equivalent to the <em>recurrence</em> formula a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}.

<h3>What is the missing element in a sequence?</h3>

A sequence is a set of elements which observes at least a <em>defined</em> rule. In this question we see a sequence which follows this rule:

n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}      (1)

Now we prove that given expression contains the pattern:

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7 + (- 1)² · 2² + (- 1)³ · 3² = 11 - 9 = 2

n = 3

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² = 2 + 16 = 18

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7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² + (- 1)⁵ · 5² = 18 - 25 = - 7

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}, equivalent to the <em>recurrence</em> formula a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}.

To learn more on patterns: brainly.com/question/23136125

#SPJ1

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