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3 years ago

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Gumballs cost $0.50 each, and jawbreakers cost $0.30 each. Bob has $3.00 to spend on candy. Create an inequality that represents

the number of gumballs and jawbreakers Bob can buy.

1 answer:

castortr0y [4]3 years ago

5 0

Answer:8 gumballs 3 jaw breakers

Step-by-step explanation:

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Help please, show steps<br>3n/7-1=1/8

goldfiish [28.3K]

Given:

$\frac{3n}{7}-1=\frac{1}{8}$

First, let's move the -1 to the right side. When we add $1 + \frac{1}{8}$ , we get $\frac{9}{8}$ .

$\frac{3n}{7}=\frac{9}{8}$

Now we can cross multiply, multiply (3n)(8) and (7)(9)

$(3n)(8)=(7)(9)$

Simplify the left side.

$24n = (7)(9)$

Simplify the right side.

$24n=63$

Divide both sides by 24 to isolate n.

$\frac{24n}{24}=\frac{63}{24}$

Simplify.

$n=\frac{21}{8}$

8 0

3 years ago

Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month

Nataly_w [17]

Answer:

It takes 13 months for the second phone to be less expensive than the first phone.

Step-by-step explanation:

First phone: y = 100 + 55x

Second phone: y = 150 + 51x

(x = number of months, y = total cost)

Make a T-Chart.

First phone: Second phone:

<u> x | y </u> <u> x | y </u>

0 | 100 0 | 150

1 | 155 1 | 201

2 | 210 2 | 252

3 | 265 3 | 303

4 | 320 4 | 354

5 | 375 5 | 405

6 | 430 6 | 456

7 | 485 7 | 507

9 | 595 9 | 609

10 | 650 10 | 660

11 | 705 11 | 711

12 | 760 12 | 762

13 | 815 13 | 813

After 13 months, the second phone will have costed $2 less than the first phone, and the price of the second will continue to be lower than the first.

5 0

3 years ago

If you horizontally stretch the quadratic parent function f(x)=x^2 by a factor of 3

Yakvenalex [24]

Answer:

The new function is (x/3)^2.

Step-by-step explanation:

If f(x) is horizontally stretched by a factor a the function is f(x/a).

So for f(x) = x^2 it becomes (x/3)^2.

5 0

3 years ago

One week, Manuel worked his regular 40 hours and 5.75 hours of overtime. If his regular

Wittaler [7]

Hope the picture will help you

4 0

2 years ago

A 15-foot pole is leaning against a tree. The bottom of the pole is 8 feet away from the bottom of the tree. Approximately how h

Karolina [17]

Poles are usually standing vertical, thus at right angle with the ground. The length of tree touching the top of pole is given by: Option D: 17 feet.

<h3>What is a right angled triangle?</h3>

A right angled triangle is a triangle having one of its angle with measure of 90 degrees.

The slant side(leaning side) of that triangle is called Hypotenuse and it is the longest side in that triangle.

<h3>What is Pythagoras Theorem?</h3>

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

$|AC|^2 = |AB|^2 + |BC|^2$

Where |AB| = length of line segment AB.

We can use the fact that the pole is standing vertical, the tree is leaning on it, so there is right angled triangle formation, and thus, we can use Pythagoras theorem.

Consider the graph attached below.

The tree is AC, The pole is AB and the distance of pole's bottom from the bottom of the tree is denoted by length of BC

We're already given that:

Pole length = |AB| = 15 feet

Distance between bottom of pole to bottom of tree = |BC| = 8 feet

The length of tree is |AC| = x feet (assume)

Then, by the Pythagoras theorem, we get:

$x^2 = 15^2 + 8^2\\\\x = \sqrt{225 + 64} \text{\: (We took positive root since length is a non negative quantity)}\\\\x =\sqrt{289} = 17 \: \rm feet$

Thus, length of AC = |AC| = 17 feet.

Thus,

The length of tree touching the top of pole is given by: Option D: 17 feet.

Learn more about Pythagoras theorem here:

brainly.com/question/12105522

6 0

3 years ago