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qaws [65]
3 years ago
15

Gumballs cost $0.50 each, and jawbreakers cost $0.30 each. Bob has $3.00 to spend on candy. Create an inequality that represents

the number of gumballs and jawbreakers Bob can buy.
Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:8 gumballs 3 jaw breakers

Step-by-step explanation:

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Please fill this out will give BRAINLIST
bixtya [17]
Rectangle: a = w x l

Square: a = a^2

Triangle: a= b x h divided by 2

Parallelogram: a = HH

Trapezoid: a = a+b
2h


5 0
3 years ago
Read 2 more answers
The length of a model car is 1/20 of the length of the actual car. If the model. is 8.7 inch long, how long is the actual car? E
madam [21]
This means that if the model is 1 in lengh then th ereal car is 20 times of that or 20 in legnth

so to find the answer, just multiply model by 20
8.7 =model
real=8.7 times 20=174
real car is 174 inches

12 inches=1 foot
conversion factor
1 ft/12in=1=convesion

so
174 times 1/12=14 and 6/12

the answer is 14 feet and 6 inches or 14.5 feet
7 0
3 years ago
Read 2 more answers
Y=2x-7<br> y=-3x+18 <br> solve by substitution
Liono4ka [1.6K]

Answer:

-x+11

Step-by-step explanation:

am not sure if this is correct but

2x-3x=-x

-7+18=11

-x+11

8 0
2 years ago
] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was
Bad White [126]

Answer:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

\hat p=\frac{502}{1045}=0.480 estimated proportion of college graduates with a mentor

p_o=0.42 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

7 0
3 years ago
I need the answer so please help it is worth 88 points
yulyashka [42]

Answer:

24

Step-by-step explanation:

If she did all 3of them today then you subtract a day from each one then it would look like this

5+4+15=24

4 0
3 years ago
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