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4 years ago

13

A pentagon has an 80° angle and 100° angle. The remaining three angels have a ratio of 2:3:4. The measure of the largest angle,

in degrees, is:

1 answer:

Genrish500 [490]4 years ago

3 0

Answer:

140,150

Step-by-step explanation:

The sum of the angles in a polygon is

180(n−3)

For a pentagon, this equals 540. Since the first 3 angles add up to 240, the remaining 2 angles must add up to 540−240=300∘

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What is the solution for x in the equation (-4(x+1)+7x=8)?

a_sh-v [17]

-4(x + 1) + 7x = 8
-4x - 4 + 7x = 8
3x - 4 = 8
3x = 8 + 4
3x = 12
x = 12/3
x = 4 <===

6 0

3 years ago

Multiply (4+I)(1-5i)

Svetllana [295]

The rule to remember for this problem is: i^2 = -1
(4 + i)(1 - 5i)
4 - 20i + i - 5i^2
4 - 19i + 5
9 - 19i

6 0

4 years ago

The location of four buildings on a coordinate grid are as follows:

Gre4nikov [31]

Answer:

3400 feet

Step-by-step explanation:

Distance between building 1 and building 2 = |5+3| = 8

Distance between building 2 and building 3 = |4+5| = 9

Distance between building 3 and building 4 = |-3-5| = 8

Distance between building 4 and building 1 = |4+5| = 9

total distance = 8 x 2 + 9 x 2 = 34

total distance in feet = 34 x 100 = 3400 feet

3 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$

Thus the coordinates of B are:

$B=(-1+\frac{2\sqrt{3} }{3},2)$

Now this point B lies on the parabola, and therefore it must satisfy the equation $y=a(x+1)(x-5).$

Thus

$2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)$

Therefore

$a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}$

$\boxed{a=-0.3575}$

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Which situations can be simulated using this spinner? Select three options.

lana66690 [7]

Choosing a color, number, or restaurant

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3 years ago