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Alenkinab [10]
3 years ago
9

Give an example of vertical angles in your home

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0
A door,picture frame,desktop,books
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8 1/2+6 1/2=<br><br><br><br><br><br> ..........NO LINK
LuckyWell [14K]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
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What are the coordinates of the point on the directed line segment from (1,-5) to
Black_prince [1.1K]

Answer:

Q (2.5, -4)

Step-by-step explanation:

Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5

AQ = (x - 1, y + 5)

QC = (10 - x, 1 - y)

AQ:QC = 1:5

so 5*AQ = QC

5(x - 1) = (10 - x)

5(y + 5) = 1 - y

Solve them:

5x - 5 = 10 - x

6x = 15

x = 15/6 = 2.5

5y + 25 = 1 - y

6y = -24

y = -24/6 = -4

Then answer is Q (2.5, -4)

6 0
2 years ago
the length of a side of a square is 10x+4 units. If the perimeter is 96 units. What is the area of the square?​
dmitriy555 [2]

Answer:

576 Units

Step-by-step explanation:

The way your teacher wants you to do it:

1. We know that multiplying a length by four gives us the perimeter of a square.

1a. Thus, we multiply the given length by four. 4(10x+4)=40x+16

1b. We know the perimeter is 96. So: 40x+16=96

2. Solving for x, we get x=2

3. Plugging our solved x into the given length  (10x+4), we see that the length of a side of the square is 10*2+4=24.

4. We know that the area of a square can be found by squaring the side of a square.

4a. 24*24=576.

5. The area is 576 units.

--------------------------------------------------------------

Easier Solution:

1. We know that the perimeter is length*4.

2. We set L to length.

2a. 4L=96

2b. L=24

3. We know that the length square is area.

4. 24*24=576.

4 0
3 years ago
Anyone good at composite functions??
sammy [17]

\bf \begin{cases} ~\hfill f(x) = &-3x+4\\ ~\hfill g(x) = &x^2\\ (g \circ f)(0)=&g(~~f(0)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(0) = -3(0)+4\implies \boxed{f(0) = 4} \\\\\\ g(~~f(0)~~)\implies g\left( \boxed{4} \right) = (4)^2\implies \stackrel{(g \circ f)(0)}{g(4)} = 16

6 0
3 years ago
Consider the parabola y = 8x − x2. (a) find the slope of the tangent line to the parabola at the point (1, 7). 6 (b) find an equ
Brut [27]
In order to find any of the info we need we have to find the first derivative of the equation.  If y=-x^2+8x,  then  y'=-2x+8.  We are told to find the slope at point (1, 7).  Using that x value in our derivative will give us the slope of the line at that point.  y' = -(1)^2+8.  So y' = 7.  That's the slope of the line.  Now we will use that slope along with the x and y coordinate in the slope-intercept form of a line to solve for b.  7 = 7(1) + b so b = 0.  Our equation then is y = 7x.  If you graph these in the same window on your calculator, you can see how perfectly that align at the given point.  It's really quite perfect.
5 0
3 years ago
Read 2 more answers
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