Solution for f(g(5)):
The notation f(g(5)) or (f • g)(5) means that we first plug 5 into the function g(x), simplify, then plug the answer that we got to f(x). We will do this step-by-step:
Step 1: Plugging 5 to g(x)
Step 2: Plugging the answer to f(x)
ANSWER: f(g(5)) is equal to 3.
Domain:
For the function f(g(x)), we can find the domain by analyzing the domains of each individual functions separately and excluding certain values depending on the restrictions from the outermost function.
However, since both functions have all real numbers as its domain, we will not need to do any exclusion anymore.
ANSWER: The domain of the function is all real numbers.
Answer:
See attached pictures.
Step-by-step explanation:
The sine and cosine functions have the forms: and . A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or . C shifts the function up and down.
The sine function always starts and ends on the x-axis.
The cosine function always starts and ends at the y=A.
6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.
The amplitude is 5.
The period is
7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).
8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.
Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).
Number 5a. is 26.78 and 5b. is 8.5
Using the Laplace transform to solve the given integral equation f(t) = t, 0 ≤ t < 4 0, t ≥ 4 is
explanation is given in the image below:
Laplace remodel is an crucial remodel approach that's particularly beneficial in fixing linear regular equations. It unearths very wide programs in var- areas of physics, electrical engineering, manipulate, optics, mathematics and sign processing.
The Laplace transform technique, the function inside the time domain is transformed to a Laplace feature within the frequency area. This Laplace function could be inside the shape of an algebraic equation and it may be solved without difficulty.
Learn more about Laplace transformation here:-brainly.com/question/14487437
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Answer:
Option B
The solution in the attached figure
Step-by-step explanation:
we have
<em>Inequality A</em>
we know that
The solution of the inequality A is the shaded area above the dashed line
The equation of the dashed line is
The slope of the dashed line is negative
<em>Inequality B</em>
we know that
The solution of the inequality B is the shaded area above the dashed line
The equation of the dashed line is
The slope of the dashed line is positive
therefore
The solution in the attached figure