Answer:
21
Step-by-step explanation:
To find the area of a parallelogram, we can split this shape up into a rectangle and two right triangles.
The rectangle:
The rectangle has dimensions of 4 by 3 centimeters therefore the area would be 4*3=12 cm squared
two right triangles:
The area of a triangle is 1/2 base * height, but since there are two triangles it would just be the base times the height. The base is 3 cm and the height is 3 so 3*3=9
Next, we add the two areas together: 12+9 = 21
Answer:
9
Step-by-step explanation:
The equation for a slope is y=mx+b, b being the y-intercept. Then, you can plug in the equation given and have 9 as your answer.
<h3>
Answer:</h3>
∠K = ∠N = 60°
∠L = ∠M = 120°
<h3>
Step-by-step explanation:</h3>
In the attached, we have renamed F to G so Brainly will let us talk about it more easily. We have also added altitude MX.
AG is also a midsegment of ΔKLM, so LM = 2×AG = 4. Then ...
... NX = AB - LM = 7 -4 = 3
and we have right ΔMXN with hypotenuse 6 and leg 3. This is recognizable as a 30°-60°-90° triangle, with the 60° angle at N.
The angle at M is supplementary to that at N (because LM ║ KN), so measures 120°
The trapezoid is isosceles, so angles K and L have the same measures as angles N and M.
Answer:
79
Step-by-step explanation:
Let's say that N is the number of cards.
So the first step is N+5, because dan bought 5 new cards.
Next his dog ate half the collection, so the 2nd piece of the problem is 
The last step is to now make it an equation. Because there are now 46 cards left,
=42.
Now solve for N which is N+5=84=> N=79
brainliest would be appreciated!
Answer:

So then we have approximately 14% of the values higher than 95.5
Step-by-step explanation:
For this case we assume that the info is given on the figure attached.
From this figure we have the following frequencies for each class
Class Frequency
___________________________
70.5-75.5 13
75.5-80.5 7
80.5-85.5 6
85.5-90.5 10
90.5-95.5 19
95.5-100.5 9
____________________________
Total 64
So we have a total of 64 values and we want to find the percentage of students that scored higher than 95.5 so we can use the formula of relative change and we got:

So then we have approximately 14% of the values higher than 95.5