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4 years ago

each brick in the wall has a dimension shown below 8 in 4 in 2.25in what is the volume of each brick?

Mathematics

1 answer:

Elena-2011 [213]4 years ago

8 0

Answer:

72 cubic inches

Step-by-step explanation:

The volume of a rectangular prism shape, such as a brick, is the product of its dimensions:

V = LWH

V = (8 in)(4 in)(2.25 in) = 72 in^3

The volume of each brick is 72 cubic inches.

You might be interested in

Which number is equivalent to 4.054

Y_Kistochka [10]

4.05400 is hopefully the answer

3 0

3 years ago

What additional information must be known to prove the triangles similar by SSS? options: A) ∠F ≅ ∠Q B) No additional informatio

swat32

Answer:

Option A) $\angle F\\$ congruent with $\angle Q$

Step-by-step explanation:

There is only information about two sides in each triangle, so there is still the need of a third piece of info which can come from an angle like $\angle F\\$ congruent with $\angle Q$ , which are angles opposite to one of the given sides on each triangle.

6 0

4 years ago

Y=Mx+b, where m= the slope and b=the y intercept Y=2x-4,slope=2andyintercept=

Dominik [7]

Answer:

slope =2

y intercept = (0,-4)

Step-by-step explanation:

y = 2x - 4

Since this is in the form y = mx+b where m is the slope and b is the y intercept

The slope is 2 and the y intercept is -4

slope =2

y intercept = (0,-4)

7 0

3 years ago

What is the least common denominator of the rational expressions below?

Lyrx [107]

Answer:

B.(x-6)

Step-by-step explanation:

12/(x^2 - 11x+30) - 43/(x^2-6x)

12/((x - 5) (x - 6)) - 43/x(x-6) [Factoring the denominator]

Both have x-6 common in the denominator,

4 0

3 years ago

The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological testdeveloped to measure the degree of Mexican/S

maria [59]

Answer:

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

(2.13264 , 2.58736)

Step-by-step explanation:

Step(i):-

Mean of the Population = 3.0

Standard deviation of the Population = 0.8

Given Mean of the sample(x⁻ ) = 2.36

Standard deviation of the sample (S) = 0.8

size of the sample = 50

Level of significance =0.05

Degrees of freedom = n-1 = 50-1 = 49

$t_{\frac{0.05}{2} , 49} = 2.0096$

Step(ii):-

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

$(x^{-} - t_{(\frac{\alpha }{2},df )} \frac{S}{\sqrt{n} } , (x^{-} +t_{(\frac{\alpha }{2},df )} \frac{S}{\sqrt{n} })$

$(2.36 - 2.0096 \frac{0.8}{\sqrt{50} } , 2.36 +2.0096\frac{0.8}{\sqrt{50} })$

( 2.36 - 0.22736 , 2.36 + 0.22736)

(2.13264 , 2.58736)

Final answer:-

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

(2.13264 , 2.58736)

7 0

3 years ago