All categories

3 years ago

I do not understand this. HELPPP!!

Mathematics

2 answers:

lesantik [10]3 years ago

6 0

Answer: I think you should try A

Step-by-step explanation:

Airida [17]3 years ago

5 0

Bro same I don't know how to do this maybe cause I don't even care anymore but its OK I hope you got the answer already

You might be interested in

In order to estimate the average electric usage per month, a sample of 81 houses was selected and the electric usage was determi

lana [24]

Answer:

Confidence interval: (1760,1956)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 81

Sample mean =

$\bar{x} = 1858 \text{ kWh}$

Population standard deviation =

$\sigma = 450 \text{ kilowatt-hours}$

Confidence Level = 95%

Significance level = 5% = 0.05

Confidence interval:

$\bar{x} \pm z_{critical}\displaystyle\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96$

$1858 \pm 1.96(\displaystyle\frac{450}{\sqrt{81}} ) = 1858 \pm 98 = (1760,1956)$

6 0

3 years ago

Determine the arc length in radians.... need major help please!!!

In-s [12.5K]

If you're supposed to find the measure of the arc:

The minor arc CD has the same measure as the central angle it subtends. In this case, arc CD has measure 50º. In radians, that's

50º * (π/180 rad/º) = 5π/18 rad

If you instead meant to ask about finding the length of the arc CD, recall that arc lengths and their subtended central angles occur in a fixed ratio equal to the ratio of the circle's total circumference to 2π rad. In other words, if L is the length of the minor arc CD, then

L /(5π/18 rad) = 2π (7 cm) / (2π rad)

==> L = 35π/18 cm

(Notice that arc measure is given radians, while arc length is given in cm, which is why I offer two different answers here.)

8 0

4 years ago

A policyholder has probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims. C

Sladkaya [172]

Answer:

0.89.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to aid in the solution to this question or problem. So, the data or parameters are;

(1). "probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims."

(2). " distributed on the interval [0,60] and are independent."

(3). "The insurer covers 100% of each claim."

So, taking (1) above we will have;

(Total probability= 0.7 + 0.2 + 0.1 = 0.1)

A = { (0.7 × 0)^2 + (0.2 × 1)^2 + ( 0.1 × 2)^2 =( 0.4) +( 0.4) = 0.8.

0.8 + total probability = 0.8 + 0.1 = 0.9.

So, from the question, we are to "Calculate the probability that the total beneﬁt paid to the policyholder is 48 or less."

Hence, P< 48/A = P < 48/0.9 = P < 53.33.

Thus, 53.33/60 = 0.89.

6 0

3 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.