Answer:
D) ["Kathy Bones", "Jill Brewer", "Joe Schnook", "Tom Smith"]
Explanation:
The context of the problem explains a computer program that sorts names in "ascending order" (A to Z) since the ASCII table has capital A start a lower number and it increases from there to capital Z.
Notice how the attached file, which is a portion of the ASCII table, shows that letters after A are also higher in decimal value than the previous letter.
With this in mind, we know that all this program does is sort by last name alphabetical order. From there, just sort the given names using that same criteria, last name alphabetical order, and the correct answer is determined.
<em>Please put "Brainliest" on my answer if it helped you out!</em>
<em>If you want to learn more about this subject, you can search:</em>
<em>- ASCII Table</em>
<em>- Lists in Programming</em>
<em>- Sorting Procedures</em>
Answer:
I am pretty sure. In my view answer is 4.0
Answer:
Configure Reservations
Explanation:
The reason you do this, is because you are getting a permanent IP address assignment.
Hope this helps!
Well actually it affects her credit. Home owners would not want to sell a house to someone who doesn't pay bills on time. It shows he/she is unreliable
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
