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pochemuha
3 years ago
13

A grade of B is worth Grade points A) 3.0 B) 80 C)2.0 D)4.0

Computers and Technology
2 answers:
Elodia [21]3 years ago
8 0

Answer:

I am pretty sure. In my view answer is 4.0

anygoal [31]3 years ago
4 0

Explanation:

Percent Grade Letter Grade 4.0 Scale

87-89. B+. 3.3

83-86 B 3.o

80-82 B- 2.7

77-79 C+ 2.3

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Please draw a diagram of a complete graph with 5 vertices (K5), its adjacency matrix and adjacency list representations.
Artist 52 [7]

Answer:

Please check the attachment.

Explanation:

The adjacency matrix is the matrix that has nodes as rows and columns. The nodes if connected is stated as 1 or else 0. And the adjacency list representation is the list with nodes and connected nodes. The nodes that are not connected are not being listed. The diagram and list as well as matrix can be found in the attachment.

4 0
3 years ago
You have installed a new sound card in your system, closed the computer case, and turned on the computer. Windows boots and you
ArbitrLikvidat [17]

The most likely problem which led to the lack of sound after the installation of the new sound card is that the '<em>sound card is not recognized or incompatible</em> '

  • The sound card is an hardware which is installed into a computer in other to allow the the system produce audio signal.

  • Without a sound card installed into a computer, then such computer would not be able to perform <em>audio</em> <em>input or produce audio signals</em>.

However, when a sound card is present and, the computer fails to produce audio signal, then the most likely problem is that, the <em>sound card installed isn't recognized</em>.

Learn more :brainly.com/question/25055825

8 0
2 years ago
Write a c++ program to print even numbers from 1 to 20​
Novay_Z [31]

Answer:

#include <bits/stdc++.h>

using namespace std;

// Function to print even numbers

void printEvenNumbers(int N)

{

cout << "Even: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are divisible by 2

if (i % 2 == 0)

cout << i << " ";

}

}

// Function to print odd numbers

void printOddNumbers(int N)

{

cout << "\nOdd: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are not divisible by 2

if (i % 2 != 0)

cout << i << " ";

}

}

// Driver code

int main()

{

int N = 20;

printEvenNumbers(N);

printOddNumbers(N);

return 0;

}

Explanation:

Note: This will find both odd and even numbers, you have to change the number above to the number of your choice

For even numbers

Even number are numbers that are divisible by 2.

To print even numbers from 1 to N, traverse each number from 1.

Check if these numbers are divisible by 2.

If true, print that number.

For odd numbers

Odd number are numbers that are not divisible by 2.

To print Odd numbers from 1 to N, traverse each number from 1.

Check if these numbers are not divisible by 2.

If true, print that number

8 0
3 years ago
Please help me idk I suck at this stuff ​
kap26 [50]
I would say the best clear answer is D, because A is a little bit unclear but I would say the best answer is D.

Why?

Mesh Topology is expensive considering more links as compared to Ring topology.


4 0
2 years ago
Implement a sublinear running time complexity recursive function in Java public static long exponentiation (long x, int n) to ca
Archy [21]

Answer:

Following are the code block in the Java Programming Language.

//define recursive function

public static long exponentiation(long x, int n) {

//check the integer variable is equal to the 0.

if (x == 0) {

//then, return 1

return 1;

}

//Otherwise, set else

else {

//set long data type variable

long q = exponentiation(x, n/2);

q *= q;

//check if the remainder is 1

if (n % 2 == 1) {

q *= x;

}

//return the variable

return q;

}

}

Explanation:

<u>Following are the description of the code block</u>.

  • Firstly, we define the long data type recursive function.
  • Then, set the if conditional statement and return the value 1.
  • Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
  • Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.
8 0
3 years ago
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