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3 years ago

Solve the following equation X = 2 and y = 4 3x + 2y + 4 =?

Mathematics

2 answers:

svetoff [14.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

3(2)+2(4)+4=

6+8+4=18

kvv77 [185]3 years ago

5 0

Answer:

Step-by-step explanation:

To solve this equation, we can substitute the values of x and y into the equation:

3x+2y+4

(3 x 2) + (2 x 4) + 4

6 + 8 + 4

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Reduce to simplest form -\dfrac{1}{4}-\left(-\dfrac{3}{5}\right)=−

Arturiano [62]

Hehehehe
Hahaha
Eat eat eat ugly ah glad to help
I did the quiz

6 0

2 years ago

The volume of the prism is 900 cubic centimeters. The height of the prism is 15 centimeters and the height of the triangular bas

NeTakaya

900=(1/2)*b*10*15
1800=150b
b=12
I hope you can figure out FC with this info.

7 0

2 years ago

Read 2 more answers

Slope=-3 goes through (1,2) whats the equation

dedylja [7]

Hi student, let me help you out! :)

..............................................................................................................................................

We are asked to find the equation of the line, using the given information:

$\star~\mathrm{-3}$ , which is the slope

$\star~\mathrm{(1,2)}$ which is a point that the line contains

$\triangle~\fbox{\bf{KEY:}}$

The slope is the number before x, in the form $\mathtt{y=mx+b}$ .

Since "m" is the slope, and we're given what the slope is, we can substitute -3 for m:

$\dag~\mathtt{y=-3x+b}$

|||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||

Now, we need to find the y intercept, "b", of the line.

Here's how it's done:

Remember the point that the line contains, (1,2)?

Well, its y-coordinate is 2; so what we do is substitute 2 for y:

$\dag~\mathtt{2=-3x+b}$

Also, its x-coordinate is 1, so we substitute 1 for x:

$\dag~\mathtt{2=-3(1)+b}$

Now, solve for b:

$\dag~\mathtt{2=-3+b}$

Add 3 to both sides:

$\dag~\mathtt{2+3=b}$

Thus, we have

$\dag~\mathtt{5=b}$

Thus, the equation of the line is:

$\bigstar\underline{\boxed{\mathtt{y=-3x+5}}}$

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

$\overline{\underline{~~~~~~~~~~~~~~~~~~~~~~~~~~}}$

3 0

1 year ago

given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ

rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0

3 years ago

If the area of a rectangle in terms of x is x2 + 15x + 26 / 6x2 and its width is x2 - 3x - 10 / 30x3 Find the length of the rect

Veseljchak [2.6K]

Answer:

The length of the rectangle is;

5x(x+13)/(x-5)

Step-by-step explanation:

Mathematically, we know that the area of a rectangle is the product of the length and width of the triangle

To find the length of the rectangle, we will have to divide the area by the width

we have this as;

(x^2 + 15x + 26)/6x^2 divided by (x^2-3x-10)/30x^3

thus, we have ;

(x^2 + 15x + 26)/6x^2 * 30x^3/(x^2-3x-10)

= (x^2+15x+ 26)/(x^2-3x-10) * 5x

But;

(x^2 + 15x + 26) = (x+ 2)(x+ 13)

(x^2-3x-10) = (x+2)(x-5)

Substituting the linear products in place of the trinomials, we have;

(x+2)(x+13)/(x+2)(x-5) * 5x

= 5x(x+13)/(x-5)

4 0

2 years ago