0.09 = 0.00 because 0 in the tenths is nearer to the 0 than the next number or digit :)
Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
y'(t) = k√(y(t)) . . . . for some proportionality constant k
y(0) = 30
y(1) = 29
We observe that a function of the form
y(t) = a(t - b)²
will have a derivative that is proportional to y:
y'(t) = 2a(t -b)
We can find the constants "a" and "b" from the given boundary conditions.
At t=0
30 = a(0 -b)²
a = 30/b²
At t=1
29 = a(1 - b)² . . . . . . . . . substitute for t
29 = 30(1 - b)²/b² . . . . . substitute for a
29/30 = (1/b -1)² . . . . . . divide by 30
1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
b = 30 +√870 . . . . . . . . simplify
The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
Answer:
a=101.223
Step-by-step explanation:
use SOCATOA
or an online calculator
https://www.calculator.net/triangle-calculator.html?vc=x&vx=z&vy=y&va=39&vz=125&vb=90&angleunits=d&x=59&y=16
Answer:
125 m/min
Step-by-step explanation:
Find the rate (speed) as follows:
25 meters
--------------------- = (125/1) meters/min = 125 m/min
(1/5) minute
This is equivalent to about 380 ft/min