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3 years ago

I NEED HELP WITH THIS PLEASE

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:

Perimeter = Side1 + Side2 + Side3

4x + 3y = 5x - 3y + x + 4y + Side3

4x + 3y = 6x + y + Side3

-2x + 2y = y + Side3

Step-by-step explanation:

I WISH IT COULD HELP

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Is the length of your classroom greater than or less than one kilometer?

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POLYGON BASICS (GEOMETRY) PLEASE HELP!!

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Answer:

Polygons are named according to the number of sides and angles they have. The most familiar polygons are the triangle, the rectangle, and the square. A regular polygon is one that has equal sides. Polygons also have diagonals, which are segments that join two vertices and are not sides.

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3 years ago

Which is bigger 1/3 or 3/5

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Answer: 3/5

Step-by-step explanation: Notice that the fractions that we are comparing in this problem have different denominators. When fractions have different denominators, they are called unlike fractions.

To compare unlike fractions, we must first get a common denominator. The common denominator of 3 and 5 will be the least common multiple of 3 and 5 or 15.

To get a 15 in the denominator of 1/3, we multiply the numerator and the denominator by 5 which gives us 5/15.

To get a 15 in the denominator of 3/5, we multiply the numerator and the denominator by 3 which gives us 9/15.

Notice that we now have like fractions since both fractions have a 15 in the denominator.

To compare like fractions, we simply look at the numerators.

9/15 - 5/15

Since 9 is greater than 5, 9/15 is greater than 5/15.

This means that 3/5 is bigger than 1/3.

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3 years ago

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The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of th

kondaur [170]

L=16
W=21

Set up a systems of equations:
x=length
y=width

xy=336
x+5=y

Use substitution to solve:
x(x+5)=336
x^2+5x=336

Solve using factoring:
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21
Since length can't be negative, l=16

To find width, plug length into the first equation:
(16)y=336
y=21

So...
L=16
<span>W=21</span>

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Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38

Katyanochek1 [597]

To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the

First, we will need to find the slope of this equation. To find this, we must simplify the equation $3x+5y=38$ into $y=mx+b$ form. Lets do it!

$3x+5y=38$
= $5y = -3x+38$ (Subtract 3x from both sides)
= $y= -\frac{3}{5}x+ \frac{38}{5}$ (Divide both sides by 5)

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is $\frac{5}{3}$ .

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

$\frac{y-y _{1} }{x- x_{1} }=m$

Substituting values, we find that:

$\frac{y-4}{x-6}= \frac{5}{3}$

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that:

$y= \frac{5}{3}x-6$ , which is our final answer.

Thank you, and I wish you luck.

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