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Free_Kalibri [48]
3 years ago
15

What is the Greatest Common Factor for 18;45

Mathematics
1 answer:
ira [324]3 years ago
3 0
The GCF for 18 and 45 is 9.
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The relation ((6, 8), (7, 10), (7, 12), (8, 16),
Brilliant_brown [7]

Answer:

x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

Step-by-step explanation:

Given the relation

  • {(6, 8), (7, 10), (7, 12), (8, 16), (10, 16)}

We know that a relation is a function that has only one output for any unique input.

As the inputs or x-values of the relations are:

at x = 6, y = 8

at x = 7, y = 10

at x = 7, y = 12

at x = 8, y = 16

at x = 10, y = 16

If we closely observe, we can check that there is a repetition of x values.

i.e. x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

8 0
3 years ago
Write 0.6 as a fraction ?
satela [25.4K]

Answer:

6/10 ; 3/5 (simplified form)

Step-by-step explanation:

To solve, note the decimal place value. Move the decimal point to the right two place values, and set it over 100

0.6 = 60/100

Simplify the fraction. Divide common factors from the numerator & denominator (20 in this case)

(60/100)/(20/20) = 3/5

3/5 is your answer

~

7 0
3 years ago
Read 2 more answers
Explain the steps you would take to complete this conversion problem
OLEGan [10]

Answer:

20909.09 grams

Step-by-step explanation:

\frac{46 \: lb}{1}  \times  \frac{1 \: kg}{2.2 \: lb}   \times  \frac{1000 \: g}{1 \: kg}  = \\ \frac{46 \: lb}{2.2 \: lb}  \times  \frac{1 \: kg}{1} \:   \times  \frac{1000 \: g}{1 \: kg}  = \\\frac{230 \: }{11 \:}  \times \frac{1 \: kg}{1 \: kg \:}\times \frac{1000 \: g}{1 \:}  = \\\frac{230 \: }{11 \:}  \times \frac{1}{1}\times \frac{1000 \: g}{1 \:}  = \\\ \frac{230}{11}g  \times 1g  \times \: 1000g

= 230 grams / 11 grams × 1000 grams = 20.90909... × 1000 = 20909.09 grams

8 0
3 years ago
Read 2 more answers
A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.
kenny6666 [7]

Answer:

p:y = 3x-10

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

y - y_1 = m(x - x_1)

The point intercept form of line can be written as:

y = mx + c

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10

which is the required slope intercept equation of line p.

4 0
3 years ago
PLZZ HELP!
dezoksy [38]
For the first one it’s h=6 and the second one is h=-3
4 0
3 years ago
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