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Free_Kalibri [48]

3 years ago

15

What is the Greatest Common Factor for 18;45

1 answer:

ira [324]3 years ago

3 0

The GCF for 18 and 45 is 9.

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The sixth grade art students are making a mosaic using tiles in the shape of right triangles.Each tile has leg measures of 3 cen

SCORPION-xisa [38]

Answer:

Am = 1500 cm²

Step-by-step explanation:

If you mean leg around the right angle a = 3 cm and b = 5 cm then :

Formula for calculating area of the right triangle is:

A = a · b / 2 since we have 200 triangles, area of the mosaic is:

Am = 200 · A = 200 · a b / 2 = 200 · 3 · 5 / 2 = 1500 cm²

Am = 1500 cm²

God with you!!!

3 0

4 years ago

In The Diagram, P, Q, R, Are Points On The Circle With Centre 0 And Diameter 14cm. Angle PQR=35 Degree. Find, Correct To One De

patriot [66]

Answer:

a

Step-by-step explanation:

because the diagram the length decimal place degree

8 0

3 years ago

the lenght of jims garden will be 10 feet more than 2 times its with. the with of jacks garden will be 5 feet less than three ti

Len [333]

Answer:

Jim: (2w+10)(w)=A

Jack: (3w-5)(L)=A

Step-by-step explanation:

2w+10=L Jim

3w-5=w

I hope this helps you

If it does a thanks and brainliest would be appreciated(trying to level up) if not pls leave a comment

7 0

3 years ago

What is the radius of a circle with an area that is three times its circumference

irinina [24]

If you divide the circumference by its diameter, the constant ratio is called Pi, which is an irrational number shown with the symbol.

Answer: Divide the circumference by its diameter!

8 0

4 years ago

In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0

kolbaska11 [484]

Answer:

$Q_3 = 56.45$ --- The third quartile

$Var = 370.18$ -- Variance

Step-by-step explanation:

Given

$Q_1 = 30.8$ -- First quartile

$Q_2 = 48.5$ --- Median

$\bar x = 42$ --- Mean

$Skp = -0.38$ --- Coefficient of skewness

Solving (9): The third quartile $Q_3$

This is calculated from

$Skp = \frac{Q_1 + Q_3 - 2Q_2}{Q_3 - Q_1}$

So, we have:

$-0.38 = \frac{30.8 + Q_3- 2*48.5}{Q_3 - 30.8}$

Cross Multiply

$-0.38 (Q_3 - 30.8)= 30.8 + Q_3- 2*48.5$

Open bracket

$-0.38Q_3 + 11.704= 30.8 + Q_3- 97.0$

Collect like terms

$-0.38Q_3 -Q_3= 30.8 - 97.0- 11.704$

$-1.38Q_3= -77.904$

Divide both sides -1.38

$Q_3 = \frac{-77.904}{-1.38}$

$Q_3 = 56.45$ --- approximated

Solving (b): The variance

First, calculate the standard deviation from:

$3IQR = 4SD$

$IQR= Q_3 - Q_1$

So:

$3IQR = 4SD$

$3(Q_3 - Q_1) = 4SD$

Make SD the subject

$SD = \frac{3}{4}(Q_3 - Q_1)$

$SD = \frac{3}{4}(56.45 - 30.8)$

$SD = \frac{3}{4}*25.65$

$SD = \frac{3*25.65}{4}$

$SD = \frac{76.95}{4}$

$SD = 19.24$

So, the variance is:

$Var = SD^2$

$Var = 19.24^2$

$Var = 370.18$

5 0

3 years ago