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Lunna [17]
3 years ago
10

Geometry help please !!!!!!!

Mathematics
1 answer:
V125BC [204]3 years ago
4 0
 the ansewr is d good luck on your test
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Analyze the pre-image ABCD. What are the vertices of the final image if T–1, –2 ◦ ry = x is applied to figure ABCD? A'' B''(3, 2
Katen [24]

No one will understand if you don't add the picture but the answer from Edgenuity is

A: (3,0)

B: (3,2)

C: (1,1)

D: (1,-1)

Your Welcome

3 0
3 years ago
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The price of of a mathematical set. was Ugx 2400 a month ago,and now it is Ugx 3000 - Find The percentage increase​
Ivanshal [37]

Step-by-step explanation:

[tex]Another example , when a straight wire is moved up and down rapidly between the two poles of a horseshoe magnet , then an electric current is produced in the wire. This is also an example of electromagnetic induction .

5 0
2 years ago
Geometry math question no Guessing and Please show work thank you
Fiesta28 [93]

Theorem

In a triangle, the measure of an exterior angle equals the sum of the measures of its two remote interior angles.

x + y = z

4n - 18 + n + 8 = 133 - 6n

5n - 10 = 133 - 6n

11n = 143

n = 13

z = 133 - 6n = 133 - 6(13) = 133 - 78 = 55

Answer: C. 55

3 0
3 years ago
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Given the equation: = 4, which property should be applied first?
Ghella [55]
This is = 4 therefore no property is applied
3 0
3 years ago
Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary
Naddik [55]
Check the picture below.

\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
\\\\\\
AB=-3\pm\sqrt{130}\implies AB=
\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
-3-\sqrt{130}
\end{cases}

since the distance AB cannot be a negative value, thus is not -3-√(130).

3 0
3 years ago
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