Does anyone know know to do this ?
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
What if i say NO?
jk
3*3=9
8+3=11
12-3=9
sp
9*11=99
2 area coverd so far
99+9=108
7*2=14
108+14=122
Lastly the tir
10-7=3
11-3-2=6
6*4=24
24/2=12
Answer:
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92
The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.