Answer:
i think its b, i just did this assignment and i got a 100% so this is correct
have a nice day :)
Step-by-step explanation:
Answer:
In general, time is not a function of temperature, but this could depend on the problem you're solving. For example, imagine a ball of metal cooling down, and data was given on how long the ball was cooling down and the temperature at the center. Someone could have fit a curve or function to the temperature to show how much time has elapsed when inputting temperature as the independent variable.
Step-by-step explanation:
10/16 are blue and red marbles, simplifying to 5/8
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Substitute z with 3.
3(4)^3
Cube 4 with 3
3(64)
Multiply 3 and 64
=192
